While loop for a menu

options=menu('Options','Report Quadrants','Plot Data','Avg. Dist.','Max Dist.','Print Ascii','Exit Program')
while (true) options<6
    options=menu('Options','Report Quadrants','Plot Data','Avg. Dist.','Max Dist.','Print Ascii','Exit Program')
for options=6
    break
end
end

I'm trying to create a while loop for a menu in order to have it remain until "exit program" is selected from the options menu. Somethings incorrect because the options value goes to 0 after the first choice.

Answer 1

[Nobel Mondal]

In my opinion, the proper way of doing this would be - using call-back functions. Please have a look if this documentation helps you. There are a few relevant examples as well.

doc uimenu

Please let me know, if this is not applicable for any specific requirement that you have.

[TS]

This works just fine, I appreciate it!

Answer 2

[Image Analyst]

You could do this:

buttonNumber = 1; % Initialize
while buttonNumber < 6
  buttonNumber = menu('Options','Report Quadrants','Plot Data',...
             'Avg. Dist.','Max Dist.','Print Ascii','Exit Program')
  if buttonNumber == 6
    break; % Get out of the loop
  end
  % else do stuff based on buttonNumber
end

[Muhammad Waqar]

This is awesome...

Answer 3

[Paulo Almeida]

Due to respect of this topic, i want to create a submenu inside one of the options, and when the user press "exit/back" ir returns t the previous menu (original one). It works just fine until i press "back" in the submenu option and it seems to enter in an infinite loop and it can't get out of the submenu.

[Image Analyst]

Paulo, this link will solve your problems with your code https://blogs.mathworks.com/videos/2012/07/03/debugging-in-matlab/ Since only you have your code, not us, we can't solve your problem directly. But that link will definitely allow you to solve it yourself.