Why I am getting error while using qammod function ?
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majdi Khlfalla
el 25 de Oct. de 2024
Editada: majdi Khlfalla
el 26 de Oct. de 2024
Hi
I am using matlab R2014a and I using the code below :
%% Simulation Parameters
numBits = 20000;
modOrder = 16;
%% Creat a source signal and apply 16-QAM modulation
srcBits = randi([0 1],numBits,1);
modOut = qammod(srcBits,modOrder,'InputType','Bit','UnitAveragePower',true);
%% Apply AWGN
SNR = 15;
chanOut = awgn(modOut,SNR);
scatterplot(chanOut)
%% Demodulate received signal
demodOut = qamdemod(chanOut,modOrder,'OutputType','Bit','UnitAveragePower',true);
I should have got the figuer above. But I am having the following error instead !
( Note : I run this code while typing my question and got the result above )
Error using qammod (line 28)
Too many input arguments.
and line 28 is found here :
27 - if(nargin>4)
28 - error(message('comm:qammod:numarg2'));
29 - end
thank you
2 comentarios
Walter Roberson
el 25 de Oct. de 2024
You should double-check your help documentation.
I suspect that back in R2014a that there was no support for 'UnitAveragePower'
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Saurabh
el 25 de Oct. de 2024
I've encountered a similar issue in the past, and I was able to resolve it by upgrading my MATLAB version to R2016a or later.
I Hope this helps
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