Scatter fails if all elements but one at index(1,1) are nan.

I am trying to use a scatter plot to visualize a 2-D histogram. I set all points with 0 hits to nan to improve the visualization of the scattering patterns. I get the following errors if there is just 1 non-NaN value in the data set:

"The logical indices contain a true value outside of the array bounds."

"Error in matlab.graphics.chart.primitive.internal.AbstractScatter/doUpdate"

In an attempt to debug the issue, I simplified the code to the following 5 test cases where the first generates the error and the others do not.

x0 = 1:14;
y0 = 1:19;
hits = nan( 19, 14 );
[x,y] = meshgrid( x0, y0 );
test_case = 1;
if test_case == 1       % fails (single non-NaN point at 1,2)
    hits(1,2) = 1;
    scatter( y(:), x(:), 20, hits(:), 'filled', 's' )
elseif test_case == 2   % passes (single non-NaN point at 1,1)
    hits(1,1) = 1;
    scatter( y(:), x(:), 20, hits(:), 'filled', 's' )
elseif test_case == 3   % passes (two non-NaN points)
    hits(1,1) = 1;
    hits(1,2) = 1;
    scatter( y(:), x(:), 20, hits(:), 'filled', 's' )
elseif test_case == 4   % passes (all points are NaN)
    scatter( y(:), x(:), 20, hits(:), 'filled', 's' )
elseif test_case == 5   % passes (random values; identify those > 0)
    hits = randi( 4, size( hits ) ) - 1;
    hits(hits<1) = nan();
    scatter( y(:), x(:), 20, hits(:), 'filled', 's' )
end

Any help would be much appreciated!

[David Goodmanson]

Hi Joe, I tried this and all five cases worked including hits(1,1) = 1. I have Matlab 2023a Update 4

[Joe Mueller]

Thanks! Walter Roberson indicated that this was a bug and fixed in 2023b.

Answer 1

[Walter Roberson]

This is fixed in R2023b (maybe slightly earlier)

There does not appear to be any public bug report about this.

[Joe Mueller]

I downloaded R2023b and the issue is resolved! Thanks for the feedback.