Linear indices from colon operator

Any array (let's consider only 2D here) can be indexed using colon operator such
array(p1:p2,p3:p4)
How can one generate list of linear indices (for that particular array) from parameters [p1, p2, p3, p4]?

 Respuesta aceptada

Matt J
Matt J el 14 de Nov. de 2024
[I,J]=ndgrid(p1:p2,p3:p4);
linear=sub2ind(size(array) , I,J);

Más respuestas (2)

Steven Lord
Steven Lord el 14 de Nov. de 2024

1 voto

See sub2ind.

2 comentarios

Stephen23
Stephen23 el 14 de Nov. de 2024
Editada: Stephen23 el 15 de Nov. de 2024
Note that in general p1:p2 and p3:p4 when used a indices like that will refer to a rectangular block of that array. So in order to get the linear indices of the entire block you will need to provide SUB2IND with subscript indices for the entire block. One way to achieve this is using NDGRID:
array = randi(9,9,9);
p1 = 3;
p2 = 5;
p3 = 2;
p4 = 5;
[X,Y] = ndgrid(p1:p2,p3:p4);
Z = sub2ind(size(array),X,Y);
array(Z)
ans = 3×4
4 7 2 6 9 9 6 7 1 2 4 8
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array(p1:p2,p3:p4)
ans = 3×4
4 7 2 6 9 9 6 7 1 2 4 8
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sub2ind() processes the indexes in parallel. All of the indices must be the same size (or else scalars)
sub2ind([4 5],1:2,1:3)
Error using sub2ind (line 61)
Subscript arguments must be scalars or arrays of the same size.

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Catalytic
Catalytic el 14 de Nov. de 2024
Editada: Catalytic el 14 de Nov. de 2024
K=createArray(size(array),Fill=sparse(0));
K(p1:p2,p3:p4)=1;
out=find(K); %linear indices

1 comentario

I would probably do instead,
K=createArray(size(array),Fill=sparse(false));
or maybe just use,
K=false(size(array))
depending on the expected size of the output.

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el 14 de Nov. de 2024

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