How to divide a matrix and find the index?

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Weiqian Jiang
Weiqian Jiang el 19 de Mayo de 2015
Comentada: Weiqian Jiang el 19 de Mayo de 2015
Hi there, I have a matrix such as a = ['hello' 'hi' 'bye';1 3 5], i want to use the 2nd column to categorize the matrix, but what i have in mind is:
x = a(a(:,2)==1,:); y = a(a(:,2)==3,:); z = a(a(:,2)==5,:);
but when there are many categorizations, i think this method can be very dumb and long, i wonder whether there is a simple way or function to deal with this?
PS: i know histc can categorize a vector and return a index matrix, but the index histc returns cannot be used to find the original index of the original matrix.

Respuesta aceptada

Walter Roberson
Walter Roberson el 19 de Mayo de 2015
[uvals, ia, ic] = unique(a(:,2));
categorized = accumarray(ic, (1:size(a,1))', [], @(v) {a(v,:)});
  2 comentarios
Weiqian Jiang
Weiqian Jiang el 19 de Mayo de 2015
thanks for your help, i've helped about accumarray and find it useful in solving my problems, although it might be difficult to understand.. thanks again!
Weiqian Jiang
Weiqian Jiang el 19 de Mayo de 2015
maybe histc and arrayfun can be easier to handle this problem [n bin] = histc(a(:,2),low:step:high) groups = low:step:high arrayfun(@(x)a(bin==x,:),groups,'uniform',0);

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