I have a 4 dimensional matrix that represents an array of arrays and I need to find the minimum value and its index in each of the sub arrays. IE I need to call min(example(:)) on example(:,:,1,1), example(:,:,1,2)... example(:,:,1,m), example(:,:,2,1)... example(:,:,2,m)... example(:,:,n,m). Any help with this would be much appreciated.

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Stephen23
Stephen23 el 26 de Mayo de 2015
Editada: Stephen23 el 26 de Mayo de 2015

0 votos

You can just use min with its optional dimension argument:
X = [4D array];
Y = min(min(X,[],1),[],2);
Here is a simple example, with a 3D array:
>> X = reshape(1:24, [2,3,4])
X(:,:,1) =
1 3 5
2 4 6
X(:,:,2) =
7 9 11
8 10 12
X(:,:,3) =
13 15 17
14 16 18
X(:,:,4) =
19 21 23
20 22 24
>> Y = min(min(X,[],1),[],2)
Y(:,:,1) =
1
Y(:,:,2) =
7
Y(:,:,3) =
13
Y(:,:,4) =
19
You can see then it has calculated the minimum of the first two dimensions only, leaving the third dimension remaining. This works for 4D arrays too. If you do not want the leading scalar-dimensions to remain, simply use squeeze to remove them:
>> squeeze(Y)
ans =
1
7
13
19

2 comentarios

Zach  Hudson
Zach Hudson el 26 de Mayo de 2015
This works to get the minimum value but I would really like the index as well.
Stephen23
Stephen23 el 26 de Mayo de 2015
Editada: Stephen23 el 26 de Mayo de 2015
This is possible, but more complicated. Here is an example for a 3D array:
>> X = reshape(randperm(24), [2,3,4])
X(:,:,1) =
7 21 12
20 6 24
X(:,:,2) =
14 3 8
22 10 15
X(:,:,3) =
19 5 16
11 4 1
X(:,:,4) =
13 23 18
2 17 9
>> [Y,idy] = min(X,[],1);
>> [Z,idz] = min(Y,[],2);
>> N = size(X,3);
>> idy(sub2ind(size(idy),ones(N,1),squeeze(idz),(1:N)')) % row indices
ans =
2
1
2
2
>> squeeze(idz) % column indices
ans =
2
2
3
1
>> squeeze(Z) % the minimum values
ans =
6
3
1
2
This can be extended to work with 4D arrays... with some effort. It might be easier to perform this operation independently for each slice of the fourth dimension.

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el 26 de Mayo de 2015

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