How to plot a 2D graph using for loop values?

Hello, Could anyone tell me what the problem is in the following code?

Many thanks.

% code:
lambda= [1.5:0.005:1.6];
llambda=length(lambda);
for di=1:llambda
k(di)=2*3.14/lambda(di)
end
lambda= [1.5:0.005:1.6];
plot(lambda,k);

[Joseph Cheng]

Whats wrong with it and why is the plot not what you're looking for? the code matches what the plot should be.

also no need for the for loop as

 if true
  lambda= [1.5:0.005:1.6];
  k=2*3.14./lambda;
  plot(lambda,k);
 end

accomplishes the same thing

[sha]

Thanks, Cheng. I would like to plot the same thing, however. using for loop. Just curious how to plot the data using for loop? Could you help?

[Joseph Cheng]

I am trying. The main question is why is the plot in your sample code not what you're trying to get. If it is then what is the question or is the question to plot within the for loop?

[sha]

If I run the code, the following errors appear:

Error using plot Vectors must be the same lengths.

Error in Untitled7 (line 7) plot(lambda,k);

How to fix this error?

Answer 1

[sha]

Thanks, Cheng. I would like to plot the same thing, however. using for loop. Just curious how to plot the data using for loop? Could you help?

Answer 2

[Image Analyst]

The code works fine:

lambda= [1.5:0.005:1.6];
llambda = length(lambda);
for di = 1 : llambda
  k(di) = 2 * 3.14 / lambda(di)
end
plot(lambda,k);

It plots with absolutely no warnings or errors about different lengths. What is the actual code you ran (it's not that , that's for sure)?

[sha]

Thanks, It works now. :)

Answer 3

[jyoti mishra]

how to plot a vector and its delayed version in matlab?

[Image Analyst]

Try using the plot() function.