How to get the index of a row from a range of values in an excel file?
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yashvin
el 12 de Jun. de 2015
Comentada: yashvin
el 13 de Jun. de 2015
I have a table in excel with 6 column values, namely A,B,C,D,E,F
Given that I specify A=50, C=59500, E=0.786
How do i find the rows in the table that contain these corresponding numbers?
See attached file Thanks
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Guillaume
el 12 de Jun. de 2015
Editada: Guillaume
el 12 de Jun. de 2015
You could use ismember if you want exact comparison (i.e your 0.786 is to be found exactly in the spreadsheet down to the last decimal value).
New in R2015a is ismembertol that allows to specify a tolerance which works better for floating point number (bearing in mind that for computers 0.1 + 0.1 + 0.1 is not equal to 0.3, when using double or single precision numbers).
m = xlsread('somefile.xlsx');
A = 50; C = 59500; E = 0.786;
rows = find(ismember(m(:, [1 3 5]), [A C E], 'rows')); %find exact values
%or
rows = find(ismembertol(m(:, [1 3 5]), [A C E], 1e-4, 'ByRows', true)); %find values within tolerance
edit: a few typos
4 comentarios
Guillaume
el 12 de Jun. de 2015
links to doc were provided for you to work out the syntax yourself.
Anyway, fixed the typos. It should work now.
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