Eliminating a for loop for faster computation

HI, FInd below part of my code .Is it possible to substitute the for loop so that it is faster and takes less computation?
time_durations=zeros(length(out),1)';
for k=1:length(out)
time_durations(k)=minutes(time_select_20000(out(k,3))-time_select_20000(out(k,2)));
end

Respuestas (1)

Walter Roberson
Walter Roberson el 26 de Jun. de 2015
Have you tried
minutes(time_select_20000(out(:,3))-time_select_20000(out(:,2)))
with no loop?

2 comentarios

yashvin
yashvin el 26 de Jun. de 2015
Yes it works! Based on your experience, in this particular case, which one would you suggest?
Walter Roberson
Walter Roberson el 26 de Jun. de 2015
Vectorize. It's clearer.

La pregunta está cerrada.

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el 26 de Jun. de 2015

Cerrada:

el 20 de Ag. de 2021

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