How can I create a ''fun=@x...'' function for integration by multipling ''fun= @x...'' functions that consists of the originals funs subarguments?

I would like to illustrate the following code but an error occurs: this code works: fun=@(x)(exp(-hlpexpvar.*x)).*(1-(x./univar(1)))

but how can I do something like this:

funone=@x exp(-hlpexpvar.*x)

funtwo=@x 1-(x./univar(1))

fun= @x funone.*funtwo

I would like to thank you in advance for any kind of help to this problem.

Answer 1

[Steven Lord]

You were close. I'm going to define values for the variables for demonstration purposes

 hlpexpvar = 1;
 univar = 2;

Now to define the three functions

 funone =@(x) exp(-hlpexpvar.*x);
 funtwo =@(x) 1-(x./univar(1));

You can't multiply function handles. However you can multiply the values returned by evaluating the function handles.

 fun = @(x) funone(x).*funtwo(x);

Let's check by comparing the integral of fun (using funone and funtwo) and the explicitly specified function fun2.

 fun2 = @(x) exp(-hlpexpvar.*x).*(1-(x./univar(1)));
 answer1 = integral(fun, 0, 1)
 answer2 = integral(fun2, 0, 1)

[Konstantinos Dragonas]

Thank you very much for your help! This is the only problem i had in my effort to make a dynamic program that will take as input a rate transition matrix and and calculate the steady state probabilities by semi markov model.

Answer 2

[chaman lal dewangan]

Thanks, I understood how to use "fun".