Solve function with integration of function of variable

hi,
I want to use solve function on integration of varible, but it is giving error like:
"A and B must be floating point scalars".
The operation is like :
syms Y; solve(integral(@(x) exp(-x),0,T)==0.5);
Can you give suggestion to solve this (or) suggest me an alternative way. Thank you.

 Respuesta aceptada

Or so :
syms x T
T0=solve(int(exp(-x),x,0,T)-0.5==0,T);
?
Best wishes
Torsten.

Más respuestas (1)

Maybe so?
out = fzero(@(x)integral(@(y)exp(-y),0,x)-.5,.5);

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el 2 de Jul. de 2015

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el 2 de Jul. de 2015

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