Quick way to sum array elements based on flag in another array?

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Ted
Ted el 14 de Jul. de 2015
Comentada: Ted el 15 de Jul. de 2015
Say I have 2 arrays: one with "clean" data, and one that tells me which data gets lost, as indicated by zeros. If an element is lost, it should be added to the next observed element. Anybody got a quick one-or-two-liner to come up with the summed array?
Example:
clean = [1 2 3 4 5 6]
lost = [1 0 3 0 0 6]
desired = [1 5 15]

Respuesta aceptada

Stephen23
Stephen23 el 14 de Jul. de 2015
Editada: Stephen23 el 14 de Jul. de 2015
Try this:
tmp = (1:numel(lost))-[0,cumsum(lost(1:end-1)==0)];
desired = accumarray(tmp.',clean).'
Tested:
>> clean = [1 2 3 4 5 6];
>> lost = [1 0 3 0 0 6];
>> tmp = (1:numel(lost))-[0,cumsum(lost(1:end-1)==0)];
>> desired = accumarray(tmp.',clean).'
desired =
1 5 15
>> clean = [40 10 50 30 40 10 50 30 40 10 50 30];
>> lost = [40 0 50 30 0 10 0 0 40 10 50 30];
>> tmp = (1:numel(lost))-[0,cumsum(lost(1:end-1)==0)];
>> desired = accumarray(tmp.',clean).'
desired =
40 60 30 50 120 10 50 30

Más respuestas (2)

Andrei Bobrov
Andrei Bobrov el 14 de Jul. de 2015
Editada: Andrei Bobrov el 14 de Jul. de 2015
desired = flip(accumarray(cumsum(lost(end:-1:1)~=0)',clean(end:-1:1)),1)';
or
desired = accumarray(cumsum(xor([0,diff(lost > 0)],lost))',clean)';
  2 comentarios
Ted
Ted el 14 de Jul. de 2015
Thanks for the help. Try:
clean = [40 10 50 30 40 10 50 30 40 10 50 30];
lost = [40 0 50 30 0 10 0 0 40 10 50 30];
It should give:
desired = [40 60 30 50 120 10 50 30];
Your solution does not.

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Sean de Wolski
Sean de Wolski el 14 de Jul. de 2015
accumarray(interp1(find(lost),1:nnz(lost),1:numel(lost),'next')',clean)
  4 comentarios
Ted
Ted el 15 de Jul. de 2015
Sorry Sean, I must have fat-fingered the test!

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