how to resolve "Conversion to cell from double is not possible." error

Can someone point out what I am doing wrong.

a=cell(1,2);
for i=1:2
   a{i}=mat2cell(zeros(8,8,2),8,8,2);
   a{1}(:,:,1)=randi(8,8);

when i run the above lines i am getting error shown below. error:"Conversion to cell from double is not possible."

how to assign or modify the values in the cell. thanks

Answer 1

[Azzi Abdelmalek]

a=cell(1,2);
for i=1:2
 a(i)=mat2cell(zeros(8,8,2),8,8,2);
 a{i}(:,:,1)=randi(8,8);
end

[Redouane Bouchou]

Thank you Azzi Abdelmalek

Answer 2

[Guillaume]

What is the purpose of the call to mat2cell here. mat2cell with the dimension arguments the same size as the matrix just puts the whole matrix into a single cell, so

{zeros(8,8,2} %does exactly the same thing as 
mat2cell(zeros(8,8,2),8,8,2) %and is much clearer.

If the intention was indeed to put the matrix into a single cell, then your loop should have been:

for i = 1:2
   a{i} = zeros(8,8,2); %or a(i) = {zeros(8,8,2)};
   a{i}(:,:,1) = randi(8,8);
end

Or:

for i = 1:2
   a{i} = cat(3, randi(8,8), zeros(8,8));
end

Or even simply:

a = mat2cell(cat(3, randi(8,8*2,8), zeros(8*2,8)), ones(1,2)*8, 8, 2)

Answer 3

[ali hamzah]

what the error (Error using Untitled18 (line 12)

Conversion to cell from double is not possible.)

% Ensure all columns except the last one are numeric

for i = 1:(width(data) - 1)

if iscell(data{:, i})

data{:, i} = grp2idx(categorical(data{:, i}));

elseif ischar(data{:, i})

data{:, i} = grp2idx(categorical(data{:, i}));

end

end