Why am I getting NaN using interp2?

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macdommy74
macdommy74 el 26 de Ag. de 2015
Comentada: macdommy74 el 26 de Ag. de 2015
  • I have a 450*90 matrix of values
  • I want to sample the matrix at 100 random sample points
However, while my interp2 function runs without errors, my output results vector contains NaN values after the 90th index.
The code below results in me getting NaN for points after the 90th index of vals - why, and how do I correct it?
Shouldn't I be able to sample 1 point from the matrix, or 50, or 100, or 1000 points?
Code:
row_vect = 1:450;
col_vect = 1:90;
[X,Y] = meshgrid(col_vect, row_vect);
V = abs(rand(450,90));
Xq = row_vect(1:100);
Yq = randi(89, 1,100);
vals = interp2(X, Y, V, Xq', Yq');
Thanks

Respuesta aceptada

Torsten
Torsten el 26 de Ag. de 2015
You try to extrapolate in Y-direction.
Read the description part for interp2 under
and you'll see why you get NaN for Y-values greater 90.
Best wishes
Torsten.
  3 comentarios
Torsten
Torsten el 26 de Ag. de 2015
Use
[X,Y] = meshgrid(row_vect, col_vect);
instead of
[X,Y] = meshgrid(col_vect, row_vect);
Best wishes
Torsten.
macdommy74
macdommy74 el 26 de Ag. de 2015
I think this worked - thanks a million!!

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Más respuestas (1)

Walter Roberson
Walter Roberson el 26 de Ag. de 2015
Your problem is your X not your Y. max(X(:)) is 90 because your first argument to meshgrid() is col_vec which is 1:90
  1 comentario
macdommy74
macdommy74 el 26 de Ag. de 2015
I think this worked - thanks a million!!

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