how to write Binary table in simple way ?
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Henry Buck
el 12 de Sept. de 2015
Comentada: Walter Roberson
el 28 de Jul. de 2019
Hi there,
1. How to create Binary code (like this one below) in a simple way?
0 0 0 0
0 0 0 1
0 0 1 0
0 0 1 1
0 1 0 0
0 1 0 1
0 1 1 0
0 1 1 1
1 0 0 0
1 0 0 1
1 0 1 0
1 0 1 1
1 1 0 0
1 1 0 1
1 1 1 0
1 1 1 1
2. how to print only the relevant rows like:
0 0 1 1
0 1 0 1
0 1 1 0
1 0 0 1
1 0 1 0
1 1 0 0
only the rows that has 2 bits that equal to 1.....
Thanks,
Henry
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Respuesta aceptada
Walter Roberson
el 12 de Sept. de 2015
What happens if you use dec2bin(13) - '0' ?
A way to calculate how many values are set in a row is to sum() the row.
You should also investigate logical indexing
12 comentarios
Walid KESSAL
el 16 de Mzo. de 2018
Here's how you can take care of that problem Mr.Henry Buck.
n=4; tab=[];
for i=0:(2^n-1)
table(i+1,:) = dec2bin(i,n);
tab = [tab;table(i+1,:)];
end
table = tab
the result is this
Walter Roberson
el 28 de Jul. de 2019
That code is redundant: just assigning into table() is enough without needing to build that tab variable.
Más respuestas (1)
Pierre Bulens
el 28 de Jul. de 2019
dec2bin function gives the table :
to get the rows containing 2 bits equal to 1, use the sum function and logical indexing
the sum function gives the number of 1s in each row,
the '== 2' part selects the wanted rows
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