Write a MATLAB program to sketch the following discrete-time signals in the time range of –10 ≤ n ≤ 10. Please label all the graph axes clearly. If the sequence is complex, plot the magnitude and angle separately. i) x(n) = u(n) – u(n – 3)

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n=-10:10;
u(1:21)=ones(1,21); %creates a unit step sequence for u(n)
%how to write a delayed version of sequence i.e for u(n-3) ?
  1 comentario
Walter Roberson
Walter Roberson el 12 de Nov. de 2024 a las 18:56
Editada: Walter Roberson el 12 de Nov. de 2024 a las 18:57
It is not possible in MATLAB to draw signals in continuous time. There are no MATLAB functions that are able to graph curves. The best that can be done is to sample a signal at high resolution and draw the sampled signal, which will be done as a series of connected straight line segments.

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Respuestas (3)

Aliya Patel
Aliya Patel el 23 de Nov. de 2018
Editada: DGM el 4 de Nov. de 2023
t = (-10:1:10)'; %%Can change the interval time by replacing 1 with 0.1
step1 = t>=0; %% For u[n]
step2 = t>=3; %%For u[n-3]
x = step1-step2;
plot(t,x) %%scatter can be used instead of plot
xlabel('time');
ylabel('amplitude');
title('x(n)=u(n)-u(n-3)');
  3 comentarios
DGM
DGM el 4 de Nov. de 2023
Editada: DGM el 4 de Nov. de 2023
Indexing looks fine, but representing this using plot() is visually misleading. I suspect that motivation is why Aliya suggested scatter(), though I think stem() would probably be better.
Paul
Paul el 12 de Nov. de 2024 a las 22:43
I think the easiest, most flexible, and intutive way is to define u[n] with an anonymous function and go from there
u = @(n) double(n>=0);
n = -10:10;
figure
stem(n,u(n)-u(n-3)) % direct connection to the problem statement

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Satadru Mukherjee
Satadru Mukherjee el 21 de Mzo. de 2020
Editada: Satadru Mukherjee el 21 de Mzo. de 2020
n1=-10:10;
x=(n1>=0);
n2=n1+3;
y=x;
u=min(min(n1),min(n2));
t=max(max(n1),max(n2));
r=u:1:t;
z1=[];
temp=1;
for i=1:length(r)
if(r(i)<min(n1) || r(i)>max(n1))
z1=[z1 0];
else
z1=[z1 x(temp)];
temp=temp+1;
end
end
z2=[];
temp=1;
for i=1:length(r)
if(r(i)<min(n2) || r(i)>max(n2))
z2=[z2 0];
else
z2=[z2 y(temp)];
temp=temp+1;
end
end
z=z1-z2;
subplot(3,1,1);
stem(r,z1);
xlabel('Time sample');
ylabel('Amplitude');
title('First signal');
subplot(3,1,2);
stem(r,z2);
xlabel('Time sample');
ylabel('Amplitude');
title('Second signal');
subplot(3,1,3);
stem(r,z);
xlabel('Time sample');
ylabel('Amplitude');
title('Signal after Subtraction');
  3 comentarios
Walter Roberson
Walter Roberson el 16 de Mayo de 2020
It appends x(temp) to the end of z1. They wrote the code using that technique because people tend to learn the [] concatenation before they gain the experience to initialize an array to full size and write at a particular in the array.
Bhargav Jyoti Saikia
Bhargav Jyoti Saikia el 27 de Mzo. de 2021
Thank you very much. This program gave a clear idea as to how to implement these functions. Took little time to understand but after little debugging got the idea. There might be easier way or easier to understand simple method to achieve the same functionality.

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Roman Mia
Roman Mia el 22 de Feb. de 2023
n=-10:10;
u=[zeros(1,13), ones(1, 8)];
stem(n,u);

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