Write a MATLAB program to sketch the following discrete-time signals in the time range of –10 ≤ n ≤ 10. Please label all the graph axes clearly. If the sequence is complex, plot the magnitude and angle separately. i) x(n) = u(n) – u(n – 3)
418 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Superman
el 15 de Sept. de 2015
Comentada: Walter Roberson
el 24 de Abr. de 2024 a las 21:50
n=-10:10;
u(1:21)=ones(1,21); %creates a unit step sequence for u(n)
%how to write a delayed version of sequence i.e for u(n-3) ?
0 comentarios
Respuestas (4)
Aliya Patel
el 23 de Nov. de 2018
Editada: DGM
el 4 de Nov. de 2023
t = (-10:1:10)'; %%Can change the interval time by replacing 1 with 0.1
step1 = t>=0; %% For u[n]
step2 = t>=3; %%For u[n-3]
x = step1-step2;
plot(t,x) %%scatter can be used instead of plot
xlabel('time');
ylabel('amplitude');
title('x(n)=u(n)-u(n-3)');
2 comentarios
Satadru Mukherjee
el 21 de Mzo. de 2020
This is wrong , your code is not taking care of the time index :-/
Satadru Mukherjee
el 21 de Mzo. de 2020
Editada: Satadru Mukherjee
el 21 de Mzo. de 2020
n1=-10:10;
x=(n1>=0);
n2=n1+3;
y=x;
u=min(min(n1),min(n2));
t=max(max(n1),max(n2));
r=u:1:t;
z1=[];
temp=1;
for i=1:length(r)
if(r(i)<min(n1) || r(i)>max(n1))
z1=[z1 0];
else
z1=[z1 x(temp)];
temp=temp+1;
end
end
z2=[];
temp=1;
for i=1:length(r)
if(r(i)<min(n2) || r(i)>max(n2))
z2=[z2 0];
else
z2=[z2 y(temp)];
temp=temp+1;
end
end
z=z1-z2;
subplot(3,1,1);
stem(r,z1);
xlabel('Time sample');
ylabel('Amplitude');
title('First signal');
subplot(3,1,2);
stem(r,z2);
xlabel('Time sample');
ylabel('Amplitude');
title('Second signal');
subplot(3,1,3);
stem(r,z);
xlabel('Time sample');
ylabel('Amplitude');
title('Signal after Subtraction');
3 comentarios
Walter Roberson
el 16 de Mayo de 2020
It appends x(temp) to the end of z1. They wrote the code using that technique because people tend to learn the [] concatenation before they gain the experience to initialize an array to full size and write at a particular in the array.
Bhargav Jyoti Saikia
el 27 de Mzo. de 2021
Thank you very much. This program gave a clear idea as to how to implement these functions. Took little time to understand but after little debugging got the idea. There might be easier way or easier to understand simple method to achieve the same functionality.
Jyothi
el 24 de Abr. de 2024 a las 17:20
DGM
ha marcado con alerta este/a respuesta
import numpy as np import matplotlib.pyplot as plt
- Define the range of n n = np.arange(0, 11)
- Calculate the exponential signal signal = np.exp(-0.1 * n)
- Plot the signal plt.stem(n, signal, use_line_collection=True) plt.xlabel('n') plt.ylabel('e^(-0.1n)') plt.title('Discrete Exponential Signal e^(-0.1n)') plt.grid(True) plt.show()
1 comentario
Walter Roberson
el 24 de Abr. de 2024 a las 21:50
This appears to be python code, but MATLAB was being asked about rather than Python.
The python code does not appear to answer the question that was asked.
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!