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Binary table - counting bits in rows

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Henry Buck
Henry Buck el 15 de Sept. de 2015
Editada: Star Strider el 15 de Sept. de 2015
Hi,
How can I print only the rows that have only two '1' bits in rows? like this one:
0 0 1 1
0 1 0 1
0 1 1 0
1 0 0 1
1 0 1 0
1 1 0 0
Thanks, Henry

Respuesta aceptada

Thorsten
Thorsten el 15 de Sept. de 2015
table= dec2bin(0:(2^4-1)) - '0';
Nones = sum(table, 2);
table(Nones==2, :)
  2 comentarios
Henry Buck
Henry Buck el 15 de Sept. de 2015
Thanks a lot, Henry
Image Analyst
Image Analyst el 15 de Sept. de 2015
table is a reserved word for a special data type in MATLAB so I would pick another variable name.
When you said "two '1' bits in rows" and gave this "0 0 1 1 0 1 0 1 0 1 1 0 1 0 0 1 1 0 1 0 1 1 0 0" (just a single row), I thought you meant "two 1's in a row", meaning two 1's that were consecutive/adjacent, so that's what my code did.

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Image Analyst
Image Analyst el 15 de Sept. de 2015
Do you have the Image Processing Toolbox? If so, it's simple to just call regionprops on each row and measure the lengths of all 1 segments. If any of the lengths = 2, then print that row with fprintf(), like this untested code:
for row = 1 : rows
thisRow = m(row, :);
labeledData = bwlabel(thisRow); % Identify each separate segment.
measurements = regionprops(labeledData, 'Area');
allLengths = [measurements.Area];
% See if any of the stretches of 1's are 2 in length
if any(allLengths == 2)
fprintf('%d ', thisRow);
fprintf('\n');
end
end

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