create 3D matrix from input file
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Chappi
el 17 de Sept. de 2015
Comentada: Chappi
el 18 de Sept. de 2015
Dear experts,
I am very new to Matlab and also don't know much about coding stuff. Would you please help me out?
I have an output file as following
1 1 1 0 372
115 -0.10495324E-08
116 -0.23828453E-07
117 -0.23688876E-07
118 -0.10215027E-08
122 -0.25753166E-12
etc
The first line is meaningless the second line, left column is the index of a 3D matrix, and the right column is its value.
As I know, this file is written out as the radius index varying fastest, the the latitude index and then the longitude index. The index that is not showed in the file is zero.
So how can I create this 3D matrix completely will all zero and non-zero element with correct position of longitude, latitude and radius?
I'm really grateful for your help !
Chappi !
2 comentarios
Stephen23
el 18 de Sept. de 2015
Editada: Stephen23
el 18 de Sept. de 2015
Your explanation is nice, but it really is much easier and more reliable if you simply upload the file for us to try it out. You can do this by clicking the paperclip button above the text box, and then clicking both Choose file and Attach file* buttons.
Respuesta aceptada
Stephen23
el 18 de Sept. de 2015
Editada: Stephen23
el 18 de Sept. de 2015
This code will read the file data into two cell arrays, one containing the header numeric data, the other containing the indices and data. Because this format repeats in four times in the file, the cell arrays have length four.
opt = {'CollectOutput',true};
str = fileread('matrix.txt');
[idb,ide] = regexp(str,'^(\s+\d+){5}\s*$','lineanchors');
idb(end+1) = 1+numel(str);
for k = numel(ide):-1:1
C(k) = textscan(str(idb(k):ide(k)),'%d%d%d%d%d',opt{:});
D(k) = textscan(str(ide()+1:idb(k+1)-1),'%f%f',opt{:});
end
If the first column of data are array indeices then it is very easy to use these to place that data into a 3D array, but you have to tell us the array size.
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