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Normalized cross-correlation function

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Manolis Michailidis
Manolis Michailidis el 18 de Sept. de 2015
Comentada: devi sowjanya el 6 de Mzo. de 2021
Hello, i am trying to write a normilized cross-correlation method function , but i can't complete it. Here are the details of the formula :
My code is
x=rand(1,1000);
N=length(x); %// length of signal
n1=128; %// length of window
xf=framing(x,n1,n1/2,rectwin(n1)); %this function frames the signal i will get xf(128,14)
win_num=size(xf,2);
for col=1:win_num
for m=1:n1+1
for n=1:n1-m
ccor(m,col)=sum(xf(n+m,col)*(xf(n,col)))/ sqrt(sum(xf(n)^2)*sum(xf(n+m)^2) );
end
end
end
Note that i want to see the correlation values betwen -1 and 1 like in the figure but instead i get
.
  1 comentario
devi sowjanya
devi sowjanya el 6 de Mzo. de 2021
Can you please provide the framing function code

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Respuesta aceptada

Kirby Fears
Kirby Fears el 21 de Sept. de 2015
Editada: Kirby Fears el 21 de Sept. de 2015
Hi Manolis,
To directly replicate what the equations say (shifting indices with +1), the calculation would look more like this:
x=rand(1,1000);
N=length(x); %// length of signal
n1=128; %// length of window
xf=framing(x,n1,n1/2,rectwin(n1)); %this function frames the signal i will get xf(128,14)
win_num=size(xf,2);
% M0=???
ccor=NaN(M0+1,win_num);
for col=1:win_num
for m=1:M0+1,
[term1,term2,term3]=deal(0);
for n=1:N-m,
term1=term1+xf(n,col)*xf(n+m,col);
term2=term2+xf(n,col)^2;
term3=term3+xf(n+m,col)^2;
end
ccor(m,col)=term1/sqrt(term2*term3);
end
end
You would just need to explicitly specify M0. This calculation can be simplified as follows:
x=rand(1,1000);
N=length(x); %// length of signal
n1=128; %// length of window
xf=framing(x,n1,n1/2,rectwin(n1)); %this function frames the signal i will get xf(128,14)
win_num=size(xf,2);
% M0=???
ccor=NaN(M0+1,win_num);
for col=1:win_num
for m=1:M0+1,
term1=sum(xf(1:N-m,col).*xf(1+m:N,col));
term2=sum(xf(1:N-m,col).^2);
term3=sum(xf(1+m:N,col).^2);
ccor(m,col)=term1/sqrt(term2*term3);
end
end
I don't have the toolbox required to run this code, so it may have bugs. Hope this helps.
  1 comentario
Manolis Michailidis
Manolis Michailidis el 29 de Sept. de 2015
Thank you i finally solved it, for M0=n1-1 shifts i had to replace in the loops N with n1 and it works. I get the results i want , from the start i wanted the correlation to be biased it the region [-1 1] and that's what i get. So thanks a lot for your effort.

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Más respuestas (2)

Kirby Fears
Kirby Fears el 18 de Sept. de 2015
Editada: Kirby Fears el 18 de Sept. de 2015
Hi Manolis,
You are looping n and m by starting at 1, but in the formula you posted the sum starts at 0. You will need to correct your calculations to include the 0 terms in the summation. You should also consider pre-allocating "ccor" to save yourself some computational time.
You may have access to the xcorr function which calculates cross correlations. It has several options to control normalization.
Hope this helps.
  2 comentarios
Manolis Michailidis
Manolis Michailidis el 18 de Sept. de 2015
Hello, indeed the index starts from 0 but matlab's indexing is from 1 so i considered that in mind. The pre-allocating is not my primary concern , on the other hand i know the xcoor(...,'coeff') can do it , but i wanted to write my own function , so do you have any ideas where is the error? thank you.
Kirby Fears
Kirby Fears el 21 de Sept. de 2015
Indeed the loop variables are only used as indices, so you are correct. My mistake. I assumed the loop variables were also used as numeric values in the summand. I'm writing another answer below.

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Image Analyst
Image Analyst el 29 de Sept. de 2015
Do you have the Image Processing Toolbox? If so, why not just use the built-in function normxcorr2()?
  1 comentario
Manolis Michailidis
Manolis Michailidis el 29 de Sept. de 2015
Editada: Manolis Michailidis el 29 de Sept. de 2015
Yes i have it, i was just curious and wanted to confirm the result with the matlabs, anyway thank you i will take a look at the function you mentioned. It's always nice to learn something new.

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