How to find maximum of individual cell array in its specific range

Hi all, I have a cell structure consisting of multiple vectors(arrays)of different lengths. I want to find the maximums of these vectors and their locations at their specific ranges; let's say I want to find the maximum of the first halves of the vectors and of the second halves. I tried to accomplish this task by using the findpeaks function, but it is not necessary. So far I managed to write:

 cut_Force... 1x123            1549992  cell
 cut_Time...  1x123            1549992  cell

(data attached)

 for c = 1 : length(cutTime)
    [pks{c},locs{c}] = findpeaks(cut_Force{c},'MinPeakDistance',600);

    indesiredrange1 = locs{c} > 0 & locs{c} < round(cellfun(@length,cutTime(c))/2);
    Firstmax{c} = max(pks{c}(indesiredrange1));
    locs_subset1{c} = locs{c}(indesiredrange1);

    indesiredrange2 = locs{c} > round(cellfun(@length,cutTime(c))/2) & locs{c} < round(cellfun(@length,cutTime(c)));
    Secondmax{c} = pks{c}(indesiredrange2);
    locs_subset2{c} = locs{c}(indesiredrange2);
 end

However, this code doesen't work for all the data (cutForce) I want to run through because of the 'MinPeakDistance', which in some cases gets more than one maximum and in some cases none. But I want to get exactly one maximum for every half of each vector. So I am looking for a more robust way.

I also tried to find these maximums using for loops, but also failed due to lack of programming knowledge:

Firstmax = [];
Secondmax = [];

%Searching for the maximums in the first halves of the vectors

for c = 1 : length(cutTime)
    for d = 1 : round(cellfun(@length,cutTime(c))/2)
        Firstmax{c} = max(cutForce{c}(d)); %I guess this loop is not appropriate
    end    
end

% Searching for the maximums' locations - this could probably be written in the
% previous loop

idx1 = [];
for c = 1 : length(cutTime)
    idx1{c} = find([cutForce{c}] == Firstmax{c}); % ??
end

for c = 1 : length(cutTime)
    for d = round(cellfun(@length,cutTime(c))/2) : (cellfun(@length,cutTime(c)))
        Secondmax{c} = max(cutForce{c}(d));
    end    
end

idx2 = [];
for c = 1 : length(cutTime)
    idx2{c} = find([cutForce{c}] == Drugi_vrh{c}); 
end

I am sure this can be done much easier in a shorter way. Any help will be appreciated.