How I solve this equation (delta function)
2 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
inas jawad
el 1 de Oct. de 2015
In the equation for delta as shown in the image attached there is a term being used.... m(j-1) if I take m to be the 1x256 matrix that we got by gamma correction and say that m(j-1) means the j-1 th term of m matrix, then: ==>for j=1, m(0) does not exist, so I have changed that to m(j). If that is the case then, H is a matrix of zeros (256x256). That cannot be right because that means that the output pixels are all 0, irrespective of input pixel values. So Please can help me
0 comentarios
Respuesta aceptada
Thorsten
el 1 de Oct. de 2015
Editada: Thorsten
el 1 de Oct. de 2015
In this formula m is not a 1x256 matrix, but a function that you can define as, e.g.,
gamma = 2.3; N = 256;
m = @(j) N*(j/N)^gamma;
So m(0) is NOT the zero'th entry of m, which is not defined, but the call of function m with argument 0.
0 comentarios
Más respuestas (0)
Ver también
Categorías
Más información sobre Gamma Functions en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!