Delete elements from a vector that are less or equal than the elements immediately before them

Hello

I would like to delete all the elements in a vector that are equal or less than the elements immediately before them. If I use a "for" loop, the vector changes its size when the previous condition is met and I get an error because the last element of the vector cannot be accessed.

Example: time = [0; 1; 2; 2; 3; 4; 5; 6];

for i = 1:(length(time)-1) if time(i+1) <= time(i) time(i+1) = []; end end

Error message: "Attempted to access time(8); index out of bounds because numel(time)=7."

Many thanks in advance.

Answer 1

[Guillaume]

The solution to your problem is to collect the indices to delete in the loop and perform the deletion all at once after the loop.

Even better, is not to use a loop at all

   time = [0; 1; 2; 2; 3; 4; 5; 6];
   time([false; diff(time) <= 0]) = []

[Steve Carroll]

Many thanks, that works fine!