Remove the background of an image
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How can I remove the background of this image including the shadow? Actually I want to work with only the face and without the illumination conditions.
2 comentarios
Image Analyst
el 27 de Oct. de 2015
Editada: Image Analyst
el 27 de Oct. de 2015
For just this image specifically (fairly easy)? Or for any image of a head against any varying or cluttered background (ranges from easy to difficult/impossible)? And exactly what does removal mean to you? Set to black? Crop out? Something else?
Respuestas (2)
Image Analyst
el 27 de Oct. de 2015
First of all, fix your horrible image capture conditions. I mean, why have a strong light coming in from the side that creates huge dynamic range and strong deep shadows. Get a uniform background. This is an easy thing to do photographically. Secondly, use a color camera - it will be easier to find the uniform background in that case. Post an image like that once you have it and then we can proceed.
Aj_ti
el 9 de Oct. de 2016
Editada: Aj_ti
el 9 de Oct. de 2016
I can't say this is the best way, but I'm currently apply this to crop the face images, removing the background and hair part as shown in the picture below:
This my reference image.
What I did is I crop (manually, using photo editor) 1 face image as a reference. Then, I apply feature point detection on the face and make 6 points as reference points (I'm using the points on eyes). Doing the same for other face images that you want to process to get the 6 points. Lastly, perform/calculate the geometric transformation as the code below and perform image warp.
[tform,inlierPtsDistorted,inlierPtsOriginal] = estimateGeometricTransform(matchedPtsDistorted,matchedPtsOriginal,'similarity');
showMatchedFeatures(ori,img,inlierPtsOriginal,inlierPtsDistorted);
outputView = imref2d(size(ori));
Ir = imwarp(img,tform,'OutputView',outputView);
This image shows points matching between reference image and probe image.
The result is as follow:
Regarding the illumination issue, histogram equalization or Retinex able to solve it. There are a lot of algorithm for illumination normalization.
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