For loop beginner question
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I just want to know why my loop is not working properly.
x = 0;
t = transpose(1:1:62403); %time vector [s]
n = length(x);
xdot = zeros(n, length(t));
for i = 1:n;
NH3_in= (((M_urea/2).*(X_H4N2CO*rho_air))./(M_H4N2CO.*((M_exhgas+(M_urea/2))))); [mol/m3]
NH3_in_ppm = ((NH3_in.*M_air)./rho_air).*10^6; % [ppm]
subplot(4,1,1);
plot (NH3_in_ppm);
ylabel('NH3 In [ppm]','fontsize',12,'FontWeight','bold','color','r')
ylim([0 1500]);
mass = ((M_exhgas)+(M_urea/2)); %Exh_vel = ((mass)/(rho_air*A)); [m/s]
Gamma = ((Exh_vel)./(L*omega));
T = ((1./Tbscr_K)-(1./T_ref));
r_sn = Ar .* (exp((-E_NO2./R_gasconstant).*(T))); [m3/mol/s]
A = NOx_in; [mol/m3]
B = 1+((r_sn.*x)./(Gamma));
h1 = A./B ; [mol/m3] (h1)
subplot(4,1,2);
h1_ppm = ((h1.*M_air)./(rho_air)).*10^6; % [ppm] Conversion
plot(h1_ppm);
%ylim([0 40])
ylabel('NOx Out [ppm]','fontsize',12,'FontWeight','bold','color','r')
%
r_a = Aa * (exp((-E_a./R_gasconstant).*(T)));
r_d = Ad * (exp((-E_d./R_gasconstant).*(T)));
h2 = ((NH3_in.*Gamma) + (r_d.*x))./((Gamma)+(r_a.*(1-x))); [mol/m3] (h2)
subplot(4,1,3);
h2_ppm = ((h2*M_air)/rho_air)*1e6; % [ppm] Conversion
plot(h2_ppm);
ylabel('NH3 Out [ppm]','fontsize',12,'FontWeight','bold','color','r')
%ylim([0 500]);
%
xdot(i,:) = (Gamma.*(NH3_in+h1-h2-NOx_in)); [-]
subplot(4,1,4);
x = x + xdot(i,:) ; %integeration
plot(x);
%ylim([0 1.5])
xlabel('Time [s]','fontsize',12,'FontWeight','bold','color','r')
ylabel('surface Coverage','fontsize',12,'FontWeight','bold','color','r')
end
the formula written for 'B' in the above script doesnt take the iterative x value. its just taking zero in all the iteration.
where is the loop going wrong?
8 comentarios
Adam
el 4 de Nov. de 2015
Have you put a breakpoint in and looked at all the components? For B to be 0 every time suggests that ((r_sn.*x)./(Gamma)) equals -1 all the time. It should be easy to at least gather some more information by debugging.
Heartrin
el 4 de Nov. de 2015
Adam
el 4 de Nov. de 2015
So this line must be evaluating to 0 every time through the loop:
xdot(i,:) = (Gamma.*(NH3_in+h1-h2-NOx_in));
but this is still easiest to check with breakpoints. It is almost impossible for someone to just glance at a complex piece of code and pick out why the result of a whole chain of equations might evaluate to 0
Heartrin
el 4 de Nov. de 2015
Adam
el 4 de Nov. de 2015
No, in the editor add a breakpoint on the key line by clicking in the margin of the file.
You can add then programmatically as well I think, but I never do.
Heartrin
el 4 de Nov. de 2015
Thorsten
el 4 de Nov. de 2015
We need the values of all variables and the formula you try to implement to give some further advice.
Heartrin
el 4 de Nov. de 2015
Respuesta aceptada
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