sum of function handle

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Heborvi
Heborvi el 15 de Dic. de 2015
Comentada: Matt J el 15 de Dic. de 2015
Dear all, i have the following function:
sum_{1<=i<j<=n}(X_i-X_j)
and i need to write it as function handle. Can anyone help me please. Best regards.
  4 comentarios
Guillaume
Guillaume el 15 de Dic. de 2015
Your function does not appear to be the same thing at all as the expression you wrote in your question. Why is there a third iterator k, why is there a square ^2 and later a square root sqrt ?
Heborvi
Heborvi el 15 de Dic. de 2015
Editada: Heborvi el 15 de Dic. de 2015
X is a matrix (n x q), each X_i is a vector in R^q. My function is the following:
sum_{1<=i<j<=n} abs( (sqrt(sum_{k=1}^{q} (X(i,k)-X(j,k))^2)-D(i,j)) )
In the first question, i have introduced a simple problem to show how the summation of function handle works.

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Respuestas (3)

Guillaume
Guillaume el 15 de Dic. de 2015
"I need to write it as function handle". Why do you need it? As Adam says, work it out as a normal function.
Anyway:
sumdiff = @(x) sum(diff(x(nchoosek(1:numel(x), 2)), [], 2)); %assume x is a vector
The way this works:
  • nchoosek returns all the possible combinations of i and j that satisfy 1<=i<j<=n
  • these combinations are use to index the original array as two columns, x(i) in the first column, x(j) in the second
  • diff calculates the difference between the 2nd and 1st column
  • sum sum all the differences
  4 comentarios
Heborvi
Heborvi el 15 de Dic. de 2015
Editada: Heborvi el 15 de Dic. de 2015
If X is a matrix, this function works? it is possible to include a loop in an handle function? (my algorithm take the fuction as handle function )
Adam
Adam el 15 de Dic. de 2015
Editada: Adam el 15 de Dic. de 2015
You can include anything you like in a handle function if it isn't an anonymous function.
You literally just define your function and then use function handle syntax to create a handle to it. The function could be 5000 lines long if you really want (obviously not advisable!), e.g.
function s = sumdiff(x)
...
end
f = @(x) sumdiff(x)
s = f(x);

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Matt J
Matt J el 15 de Dic. de 2015
f=@(X) sum( reshape( triu( bsxfun(@minus, X(:),X(:).'),1), [],1) )

Matt J
Matt J el 15 de Dic. de 2015
g=@(X) (length(X):-1:1)*X(:) - sum(cumsum(flip(X)))
  3 comentarios
Adam
Adam el 15 de Dic. de 2015
doc flip
Matt J
Matt J el 15 de Dic. de 2015
if X is a matrix, flip(X) works?
I've been assuming -- as your original post assumes -- that X is a vector.

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