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using structures and for loops

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Inti Vanmechelen
Inti Vanmechelen el 22 de Dic. de 2015
Cerrada: MATLAB Answer Bot el 20 de Ag. de 2021
I know I'm supposed to use vectorization instead of for loops, but I have to finish this assignement this way so I hope someone is willing to help me anyway.
This is my code:
names2 = {'soleus' 'tibant' 'gaslat' 'vaslat' 'rectfem' 'hamlat'};
Vars2 = {soleus, tibant, gaslat, vaslat, rectfem, hamlat};
nvars = length(Vars2);
for s = 1:1:nvars
for idx=1:10
P(idx).(names2{s}) = zeros(100,3);
end
end
for k = 1:3
for s = 1:1:nvars
for idx=1:10
P(idx).(names2{s})(:,k)= Vars2{s}.(motion{k})(:,1);
end
end
end
When I open P, it contains the same values for P(1).soleus, P(2).soleus, P(3).soleus, ...P(10).soleus,
while all of them should be different since they are data from different subjects.
'soleus' 'tibant' 'gaslat' 'vaslat' 'rectfem' 'hamlat' are structures containing 3 matrices: Gait(100x10), StairUp(100x10) and StairDown(100x10)
The number of colums (10) equals the number of subjects.

Respuestas (1)

Guillaume
Guillaume el 22 de Dic. de 2015
"P contains the same values for P(1).soleus, P(2).soleus, P(3).soleus, ...P(10).soleus". Well, yes it would:
P(idx).(names2{s})(:,k)= Vars2{s}.(motion{k})(:,1);
The left hand side depends on idx, the right hand side does not, so of course, the same value is assigned for all idx. Something on the right must also depends on idx.

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