error-output image black in colour
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I have a code below for performing CLD ,i have performed till dct coefficient,ids it correct,please guide,in imshow(J),i get only black colour,please help
my image is rgb
I=imread('dock.jpg');
I=rgb2gray(I)
I=imresize(I,[512 512])% I become lena512
fun = @dct2; %dct2 is assigned as function
J = blkproc(I,[64 64],fun); % blkproc function subblocks the image by 8-8 and usign dct2 function
figure
imshow(uint8(J)) % plot the su
Respuestas (1)
Image Analyst
el 19 de En. de 2012
What is the type of J? Is it floating point, or complex? Try
imshow(J, []);
instead.
13 comentarios
Pat
el 20 de En. de 2012
Walter Roberson
el 20 de En. de 2012
I'm relatively sure that Image Analyst's legal name is not Walter.
imshow(J, [])
should be able to handle negative and positive values mixed.
Walter Roberson
el 20 de En. de 2012
By the way, if most of the values are near 0, but one of the values is much more (say near 255), then because the entire range of values must be covered, all of the values near 0 could come out black, and the one much larger value would come out white.
Check max(J(:)) and min(J(:))
Pat
el 20 de En. de 2012
Image Analyst
el 20 de En. de 2012
That's fine, just know that imshow is linear - it linearly scales your data between 0 and 255 for display. If you have a really skewed distribution or some real outlier values (like salt and pepper noise), you can either reassign them or run your image through imadjust().
Pat
el 22 de En. de 2012
Image Analyst
el 22 de En. de 2012
No. imshow() simply displays the image - it's not a whole complicated image processing technique like that.
Pat
el 23 de En. de 2012
Image Analyst
el 23 de En. de 2012
As like *what*??? We told you how to display images.
Walter Roberson
el 23 de En. de 2012
I'm still relatively sure that Image Analyst's legal name is not Walter.
Pat
el 23 de En. de 2012
Image Analyst
el 23 de En. de 2012
I've never used CLD so I don't have any code for it, so you're on your own. Walter's right, though it's a very fine and respectable name, my name isn't Walter.
Pat
el 24 de En. de 2012
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