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Error when Indexing and object + OOP

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Armindo
Armindo el 27 de En. de 2016
Comentada: Adam el 28 de En. de 2016
Hi,
Can anyone explain me why if I add and objet (PipeLine) to a property (PipeBolt) of another object (Bolt) like:
Bolt(1,1).PipeBolt = PipeLine;
this works well
but if I use:
Bolt(1,1).PipeBolt(N,1) = PipeLine(N,1);
I get an error like: The following error occurred converting from PipeLineObj to double: Conversion to double from PipeLineObj is not possible.
% PipeLine(instance) --> PipeLineObj (class) % Bolt (instance) --> PipeLineBolt (class)
How can I solve this error?

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Adam
Adam el 27 de En. de 2016
It likely depends what you are doing before that code. You would be best to pre-size your array of objects with e.g.
Bolt(1,1).PipeBolt = PipeLine.empty(N,0);
to ensure that the property is set to be of the type 'PipeLine', otherwise it will be a double by default, like all variables, so if you didn't explicitly instantiate it and then try to set e.g. its 7th element it will have created it as a double and be expecting a double to be given to it, not some other object type.
In general I initialise all my properties that are to be some other object as e.g.
myProp = SomeClass.empty;
or something like the example above if I expect it to be an array of objects. I cannot remember off the top of my head though - just doing the above and telling it the type of object without presizing may well be enough that your code causing an error would work because it knows the object type beforehand.
  1 comentario
Armindo
Armindo el 27 de En. de 2016
Thank you Adam, you are completely right. I do not initialised the object properly.

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Más respuestas (1)

Armindo
Armindo el 27 de En. de 2016
I solve the other issue but now I have this error:
Assignment has more non-singleton rhs dimensions than non-singleton subscripts
when I do this Bolt(1,1).PipeBolt(2,1)= PipeLineObj.empty
This should not work?
  1 comentario
Adam
Adam el 28 de En. de 2016
It should work fine if Bolt(1,1).PipeBolt(2,1) exists and the array is of the correct type.

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