Incomplete time series, how to fill in NaN in data column?
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Anne Sofie Søndergaard
el 1 de Feb. de 2016
Comentada: Ingrid
el 1 de Feb. de 2016
Hi
I have a time series consisting of date, time, longitude and latitude. Due to errors there are gaps in my date/time but the data just continue at the next date when a position is registered. What I want is to get a complete time serie (for a year) with NaN values in Long and Lat columns when a position is missing. The data is registerede (when no errors) every three hours, so I have constructed a Date/Time vector using datenum, with values every three hours, so 2920 values (8*365) for a whole year. Now I want to put in NaN in my Long and Lat on the times that matches the errors - how can I do that? I have looked at similar questions in here, but they all seem to be a bit different or just wanting to fill in NaN in the time column.
Here is a couple of lines from my data:
Date, Time, Lat, Long, Voltage(V)
01-30-2014,18:00:33,73.09214,-54.11712,N/A
01-30-2014,21:00:33,73.09213,-54.11710,N/A
01-31-2014,00:00:34,73.09212,-54.11719,N/A
02-24-2014,00:00:33,73.09113,-54.12063,N/A
02-24-2014,03:00:33,73.09112,-54.12063,N/A
02-24-2014,06:00:33,73.09113,-54.12068,N/A
So what i want is to fill in the dates from 02-01-2014 to 02-23-2014 with date and time (I have done that) and then fill in NaN in the Long and Lat columns.
Would be gratefull for help...
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Ingrid
el 1 de Feb. de 2016
you could just first create a NaN matrix and then fill in your original values at the dates that you have them available
newData = nan(length(timeVector),2);
[~,Ia,Ib] = intersect(round(originalData(:,1:2)*100),round(timeVector*100));
newData(Ib,:) = originalData(Ia,3:4);
2 comentarios
Ingrid
el 1 de Feb. de 2016
If this helped you, could you please accept the answer so that it is marked as solved so other people know this no longer requires an answer. Thank you
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