I am trying to get the code to start at a certain value lets say 80 and start counting down from there. But I am struggling to see where to put this information into my code to make this happen.
xdt3 = 5;
xt03 = 0;
xtf3 = 60;
xt3 = xtf3:-xdt3:xt03;
x3 = zeros(1,13);
for i = length(xt3):-1:2
x3(i-1) = x3(i) - ((5 - (4 /50)*x3(i)))*xdt3;
end

2 comentarios

WhatIsMatlab-
WhatIsMatlab- el 8 de Feb. de 2016
It is a different question. Similar titles

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Star Strider
Star Strider el 8 de Feb. de 2016

0 votos

You have to make the appropriate modifications to my previous code to make your new step size work:
xdt3 = 5;
xt03 = 0;
xtf3 = 60;
xt3 = xtf3:-xdt3:xt03;
x3 = zeros(1,13*xdt3);
for i = xtf3:-xdt3:xdt3+1
x3(i-xdt3) = x3(i) - ((5 - (4 /50)*x3(i)))*xdt3;
end
This runs, so you have to decide if it gives you the result you want. Note that MATLAB will skip the indices you do not address, resulting in a significant number of zero
values in your vector. You may also want to change the initial line in the for loop to:
for i = xtf3+xdt3:-xdt3:xdt3+1

2 comentarios

WhatIsMatlab-
WhatIsMatlab- el 8 de Feb. de 2016
Thank you!! I understand what you are saying
Star Strider
Star Strider el 8 de Feb. de 2016
My pleasure!
Also, if you want only the non-zero values, this works:
X3 = x3(x3~=0);

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