Is it possible to use 'numel' in nested struct?
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
pamela sulis
el 9 de Mzo. de 2016
Comentada: Guillaume
el 9 de Mzo. de 2016
Hi! I use numel in a nested struct:
for i=1:9
for j=1:size(E(1,i).bcd,2)
for jj=1:numel(E(1,i).bcd{1,j}.b)
if(isempty(E(1,i).bcd{1,j}.b{jj}))
E(1,i).bcd{1,j}.b{jj}=''
end
end
end
end
but it gives this error
'Attempt to reference field of non-structure array.'
Is it possible that the error is in the use of numel? thanks
Respuesta aceptada
Guillaume
el 9 de Mzo. de 2016
Editada: Guillaume
el 9 de Mzo. de 2016
No, the error has nothing to do with numel. As the error says, you're attempting to access a field (b maybe) of something that is not a structure.
Assuming that E is really a structure. One of the cell array in the bcd fields does not contain a structure.
To check
for eidx = 1:numel(E)
for bcdidx = 1:numel(E(eidx).bcd)
if ~isstruct(E(eidx).bcd{bcdidx})
warning('E(%d).bcd{%d} is not a structure', eidx, bcdidx);
end
end
end
2 comentarios
Guillaume
el 9 de Mzo. de 2016
I did make a typo in my code (used idx instead of eidx, most likely you already had a idx variable in your workspac). I've fixed it now and the code should run without error.
The problem is most likely that one of your cell array bcd is empty.
Más respuestas (0)
Ver también
Categorías
Más información sobre Structures en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!