Reading a CSV file with header and times
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Good Afternoon,
I am having difficulty loading csv files into Matlab. The problem seems to be with the header (which contains strings) and the data values in two of the columns (they contain time values in 00:00 format).
I am able to ignore the header through use of the 'csvread' function, but Matlab won't load the time values and gives me the below errors.
EDU>> x = csvread('SUNY_070054005.csv', 1, 0)
??? Error using ==> dlmread at 145 Mismatch between file and format string. Trouble reading number from file (row 1, field 5) ==> :15,0
Error in ==> csvread at 50 m=dlmread(filename, ',', r, c);
The data in the CSV file are in the following format...
Date,Itime,Uglo,Udir,Udif,Stime,Sglo,Sdir,Sdif
1998-01-01,00:15,0,0,0,01:00,0,0,0
1998-01-01,01:15,0,0,0,02:00,0,0,0
I would use the wizard, but I have to import 281 csv files.
Any help would be appreciated.
Many Thanks,
Steven
0 comentarios
Respuesta aceptada
Sven
el 30 de En. de 2012
Hi Steven,
The string you've got for the dates and times aren't automatically recognised as simple dates - you'll need to read them in as strings:
fid = fopen('myFile.txt')
HDRS = textscan(fid,'%s %s %s %s %s %s %s %s %s',1, 'delimiter',',')
DATA = textscan(fid,'%s %s %d %d %d %s %d %d %d','delimiter',',')
fclose(fid)
outCell = cell(size(DATA{1},1), length(HDRS));
for i = 1:length(HDRS)
if isnumeric(DATA{i})
outCell(:,i) = num2cell(DATA{i});
else
outCell(:,i) = DATA{i};
end
end
myStruct = cell2struct(outCell, [HDRS{:}], 2);
Does this work for you? It worked for a small text file that I made from your input. You can convert stringed dates (and times) using the datestr function.
3 comentarios
Sven
el 31 de En. de 2012
Hi Steven, I've updated the answer to do this second part in a way that I thought would be useful. Keep in mind that I've used "%d" which will convert all numbers in the text files to integers. Use "%f" if you need floats.
Más respuestas (1)
Stanislav
el 26 de Mzo. de 2013
Editada: Stanislav
el 26 de Mzo. de 2013
The easiest way for me is :
path='C:\folder1\folder2\';
data = 'data.xls';
data = dataset('xlsfile',sprintf('%s\%s', path,data));
Of cource you could also do the following:
[data,path] = uigetfile('C:\folder1\folder2\*.xls');
data = dataset('xlsfile',sprintf('%s\%s', path,data));
0 comentarios
Ver también
Categorías
Más información sobre Data Import and Analysis en Help Center y File Exchange.
Productos
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!