How to store vectors with different size in a loop ?

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Ole
Ole el 23 de Mzo. de 2016
Comentada: dpb el 15 de Abr. de 2019
How to store vectors with different size and how to access them. M(k) found_roots
F = @(t) cos(t)*exp(-t);
A = @(s) arrayfun(@(s)-integral(F,-10,s),s);
Z = @(t1,t2) -integral(A,t1,t2);
interval = [-5, 5];
N = 100;
start_pts = linspace(interval(1),interval(2),N);
found_roots = [];
for k = 1:10
t2 = k;
for i=1:numel(start_pts)-1
try
found_roots(end+1) = fzero(@(t1)Z(t1,t2),[start_pts(i),start_pts(i+1)]);
end
% i
end
M(k) = found_roots % vector of different length
k
end
  2 comentarios
Benjamin
Benjamin el 15 de Abr. de 2019
But in every loop, if the size of the matrix (output here) changes Matlab gives error of different matrix sizes. Is there anysolution for that.
FYI: my Matlab code generates a matrix of [A] = n*2 and in every loop (for i = 1:10) n changes. I would like to store all A results in another B matrix.
dpb
dpb el 15 de Abr. de 2019
That's what the Answer shows...use cell array instead of "regular" array...the difference is "the curlies" the {} around the subscript, not ()

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dpb
dpb el 23 de Mzo. de 2016
Use cell array instead; the curly brackets...
M{k} = found_roots;
  2 comentarios
Ole
Ole el 25 de Mzo. de 2016
Editada: Ole el 25 de Mzo. de 2016
Thanks This works but now how to plot them .
dpb
dpb el 25 de Mzo. de 2016
"them" can be plotted, sure, but against what?

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