Roots of a function
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I have two equations:
y1 = 2sinx1;
y2 = 2cos^2(x1) + 3sin(2x2+3);
here y1 = 0 while y2 = 1.
Can anyone please tell me which approach would be the best to find out the values of x1 and x2.
Thank you.
1 comentario
Torsten
el 30 de Mzo. de 2016
x1=0
x2=(asin(-1/3)-3)/2
Best wishes
Torsten.
Respuesta aceptada
Más respuestas (1)
Vlad Miloserdov
el 30 de Mzo. de 2016
if you still need this
A=solve('0 = 2*sin(x1)','1 = 2*cos(x1)^2 + 3*sin(2*x2+3)','x1','x2');
% first ans
A.x1(1)
A.x2(1)
% second ans
A.x1(2)
A.x2(2)
5 comentarios
Muhammad Umar Farooq
el 31 de Mzo. de 2016
Torsten
el 31 de Mzo. de 2016
You have two equations - thus you will need MATLAB's "fsolve".
Best wishes
Torsten.
Muhammad Umar Farooq
el 31 de Mzo. de 2016
Torsten
el 31 de Mzo. de 2016
Please show your code.
Best wishes
Torsten.
Muhammad Umar Farooq
el 31 de Mzo. de 2016
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