Finding nearest low match in array
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Hello, I’m trying to find the nearest match of a value in an array, with the condition that it never rounds up. To explain what I mean, imagine a vector of
f= [1:0.5:5]
where I want to find the nearest low match of 2.3. To simply find the nearest match, I would use
val = 2.3
tmp = abs(f-val)
[i i] = min(tmp)
nearest = f(idx)
How do I reformulate this so it gives me the index of 2 instead? Any tips?
Note, I want it to handle exact matches and negative values as well.
Respuesta aceptada
Más respuestas (3)
Kuifeng
el 4 de Abr. de 2016
bigger_value_location = find((f-val)>0);
nearest = f(bigger_value_location(1)-1)
3 comentarios
Kuifeng
el 4 de Abr. de 2016
you are welcome. pls accept this answer if it's ok. Note (1) f values need to be sorted from small to big
This answer only works because the nearest value happens to be the first value above the search value. It would fail with
f = fliplr(1:0.5:5);
A simple way would be to set any value below 0 in your tmp to Inf, before calling min:
f = [1 1.5 2.5 3 2 4.5 5.5 5]; %shuffled values to show that ordering does not matter
val = 2.3;
tmp = val - f;
tmp(tmp < 0) = Inf;
[~, loc] = min(tmp)
Azzi Abdelmalek
el 4 de Abr. de 2016
f= [1:0.5:5]
val = 2.3
[ii,jj]=sort(f)
ii1=find(ii>val,1)-1
idx=jj(ii1)
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