how to correct this error ?

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Firas Al-Kharabsheh
Firas Al-Kharabsheh el 5 de Abr. de 2016
Comentada: Image Analyst el 5 de Abr. de 2016
% M_row to return the number of ones in each row
% M_column to return the number of ones in each column
M =[ 1 1 0 1 0 1 1 1 1 1 1 1 1 1 1
1 0 0 1 0 0 1 1 1 1 1 0 1 0 1
1 1 1 0 1 1 1 1 1 1 0 0 1 0 0
1 0 0 1 0 0 1 1 1 1 1 1 0 1 1
1 1 0 1 0 1 0 1 1 1 0 0 1 0 0
1 1 1 1 1 1 0 1 1 0 1 0 1 0 1
1 1 1 1 1 1 0 1 0 1 1 1 1 1 1
1 1 1 1 1 0 0 0 0 0 1 1 1 1 1
1 1 1 1 1 0 0 0 1 0 1 1 1 1 1
1 1 1 1 1 0 0 0 1 0 1 1 1 1 1
1 1 1 1 0 0 0 0 0 1 0 1 1 1 1
1 1 1 0 0 0 0 0 0 0 1 0 1 1 1
1 1 1 0 0 0 0 0 0 0 1 0 1 1 1
1 1 1 1 0 0 0 0 0 1 0 1 1 1 1
1 1 1 1 1 0 0 0 0 0 1 1 1 1 1 ];
[n_M,m_M]=size(M);
b_M=cell(n_M,1);
c_M=cell(1,m_M);
maxb=1;
maxc=1;
for k=1:n_M
a=[0 M(k,:) 0];
ii1=strfind(a,[0 1]);
ii2=strfind(a,[1 0]);
maxb=max(maxb,numel(ii1));
b{k}=ii2-ii1;
end
for k=1:m_M
a=[0 M(:,k)' 0];
ii1=strfind(a,[0 1]);
ii2=strfind(a,[1 0]);
maxc=max(maxc,numel(ii1));
c_M{k}=(ii2-ii1)';
end
M_row=cell2mat(cellfun(@(x) [x zeros(1,maxb-numel(x))],b_M,'un',0));
M_column=cell2mat(cellfun(@(x)[zeros(maxc-numel(x),1);x],c,'un',0));
%%find the sum numbers in each column and count them
% x to return the sum of the number
% w to return number of element in each column
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
Col=(n_M+repmat(1:n_M,m_M,1)-A'.*cumsum(A',2)).*A';
for k=1:m_M
a=Col(k,Col(k,:)~=0);
[~,~,kk]=unique(a);
col1{k,1}=accumarray(kk,1);
end
celldisp(col1)

Respuesta aceptada

Image Analyst
Image Analyst el 5 de Abr. de 2016
Editada: Image Analyst el 5 de Abr. de 2016
Wow, you sure do know how to complicate things. If you want to have M_row be "the number of ones in each row, and M_column be the number of ones in each column", you can simply do
M_row = sum(M, 2);
M_column = sum(M);
Instead of what you have:
M_row=cell2mat(cellfun(@(x) [x zeros(1,maxb-numel(x))],b_M,'un',0));
M_column=cell2mat(cellfun(@(x)[zeros(maxc-numel(x),1);x],c,'un',0));
Anyway, do you have an error that you want to ask about, but forgot to share with us?
  2 comentarios
Firas Al-Kharabsheh
Firas Al-Kharabsheh el 5 de Abr. de 2016
No No M_row does not mean the number of ones in each row
M_row mean that group of ones in each row like this
the first row is [1 1 0 1 0 1 1 1 1 1 1 1 1 1 1] which mean [2 1 10]
Image Analyst
Image Analyst el 5 de Abr. de 2016
OK, I'll tell you how, but I still want to know WHY. Perhaps it would be easier if you just named your variables appropriately, like numberOfRegionsPerRow rather than M_row
[rows, columns] = size(M);
M_row = zeros(rows, ceil(columns/2));
for row = 1 : size(M, 1)
% Extract just this row.
thisRow = M(row, :);
% Measure the lengths of all "runs" of 1s.
measurements = regionprops(logical(thisRow), 'Area');
% Extract all the lengths into one vector.
allLengths = [measurements.Area];
% Assign them to the left-most part of the M-Row row.
M_row(row, 1:length(allLengths)) = allLengths;
end

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