I am having trouble with a problem I am working on. The code works until I get to the next step which is a menu asking if the player wants to play the same game again. I can't seem to get it to loop back to the correct spot.
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|i=1 while i>=1; choice = menu('Do you want to play a game?: ','yes','no') if choice == 2 error('Program will terminate'); elseif choice ==1 games = menu('Select a Game','Dunko','Bouncer','Munchies') end
if games ==1
difficulty = menu('Select desired level of difficulty','Easy','Moderate','Hard')
elseif games ==2
difficulty = menu('Select desired level of difficulty','Easy','Moderate','Hard')
elseif games ==3
difficulty = menu('Select desired level of difficulty','Easy','Moderate','Hard')
end
if games == 1 && difficulty == 1
Dunko = Dunko(1)
elseif games == 1 && difficulty == 2
Dunko = Dunko(2)
elseif games == 1 && difficulty == 3
Dunko = Dunko(3)
elseif games == 2 && difficulty == 1
Bouncer = Bouncer(1)
elseif games == 2 && difficulty == 2
Bouncer = Bouncer(2)
elseif games == 2 && difficulty == 3
Bouncer = Bouncer(3)
elseif games == 3 && difficulty == 1
Munchies = Munchies(1)
elseif games == 3 && difficulty == 2
Munchies = Munchies(2)
elseif games == 3 && difficulty == 3
Munchies = Munchies(3)
end
fprintf = ('Thank you for playing')
replay = menu('Do you wish to repeat the game?','yes','no');
if replay == 1
???????????
end
fprintf = ('Thanks for playing')|
5 comentarios
That if-else statement would surely be a lot simpler if you just did:
if games == 1
Dunko( difficulty );
elseif games == 2
Bouncer( difficulty );
else
Munchies( difficulty );
end
to get rid of the needless extra cases.
Equally there is no need for the first series of if statements since every case does the same thing. Just put
difficulty = menu('Select desired level of difficulty','Easy','Moderate','Hard')
without an if statement if there is no difference in action whichever game you choose.
I'm also not sure what you are doing with a line like:
Bouncer = Bouncer(2)
If Bouncer is a function as I assume it is you certainly don't want to assign the output of this to a variable of the same name that will subsequently over-write the function (which could potentially cause the solution in my answer below to not work - I haven't tested it).
Antonia Davis
el 12 de Abr. de 2016
Adam
el 12 de Abr. de 2016
Can you format the top part of your code in the same way as the rest please. It is difficult to see the proper code flow as it is currently.
Adam
el 12 de Abr. de 2016
You probably want a
while true
external loop though. Yours is using i >= 1, but for the code you have shown you never increment i and unless you are going to use i in some way there is no need to have it there for what is effectively an infinite loop until a break condition is met.
Antonia Davis
el 12 de Abr. de 2016
Respuestas (1)
You should just be able to do something like:
while true
difficulty = menu('Select desired level of difficulty','Easy','Moderate','Hard')
if games == 1 && difficulty == 1
...
end
fprintf = ('Thank you for playing')
replay = menu('Do you wish to repeat the game?','yes','no');
if replay == 0
break;
end
end
end
editing your existing code in the obvious places to add the new components. This is assuming you mean you want to play the same game and difficulty on answering yes to the question.
2 comentarios
Antonia Davis
el 12 de Abr. de 2016
Adam
el 12 de Abr. de 2016
I edited my answer. The first part should be handled just by moving the difficulty menu call inside this inner while loop as my edited answer shows.
If the user chooses 'No' then this inner while loop exits and you are returned to the outer while loop which will do whatever it does next.
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