Create n matrix from one matrix according to elements of a column?

I have a sorted matrix (according to the element of the third column)

A = [ 4 2 0 ;3 7 0 ; 8 9 3 ; 7 5 3; 4 4 3]

I want to get n matrix (in this case 2) from A, according to the value of the element of the third column, to get

M1 = [ 4 2 0 ; 3 7 0] 
M2 = [8 9 3 ; 7 5 3; 4 4 3].

I know how many matrix I will have and the different elements to study using the function 'unique' that provide me a matrix (for this case) B=[0;3].

I tried with the functions 'genvarname' and 'eval' but I didn't find a good solution.

Answer 1

[Andrei Bobrov]

[~,~,c] = unique(A(:,end));
M = accumarray(c,(1:size(A,1))',[],@(x){A(x,:)});

[Sleh Eddine Brika]

It's so wonderful thank you !A really interesting command, but I really need to get separated Matrix and do you know how to dynamically generate matrix name

[Andrei Bobrov]

I am corrected. Thank you Azzi

Answer 2

[Azzi Abdelmalek]

A = [ 4 2 0 ;3 7 0 ; 8 9 3 ; 7 5 3; 4 4 3] 
[ii,jj,kk]=unique(A(:,3))
out=accumarray(kk,1,[],@(x) {A(x,:)})

% the first matrix and the second are

out{1}
out{2}

It's not a good idea to generate multiple names http://matlab.wikia.com/wiki/FAQ#How_can_I_create_variables_A1.2C_A2.2C....2CA10_in_a_loop.3F

[Sleh Eddine Brika]

Thank you for your answer, but there is a problem with the variable kk. Anyway I think I had found a good solution. I really need to affect names because there a lot and a lot of operations to do with those new matrix so i need to find a way to call them.

[Y,I]=sort(A(:,3));
B=A(I,:)
L=unique(B(:,3))
for j=1:length(L)
   M{j} = [];
   for i=1:length(B1)
      if isequal(B1(i,3),L(j))
          M{j}=[M{j};B1(i,:)];
      end
   end
end

[Azzi Abdelmalek]

@Sleh Eddine, it's easier to call your matrices with one variable and indices: out{1}, out{2},... then using multiple variables!

[Sleh Eddine Brika]

Ok, I will do it like you said ,thank you very much for your help Mr Azzi