how to use regexp in a more complex example
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Leonardo Wayne
el 19 de Abr. de 2016
This MATLAB code returns an array called "selected motors" at line 23 via user entry.
I would like to get all the indices(row number) of cells in raw2 1st column that have the string 1-2-3 and the selected motors values in them.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/161786/image.png)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/161788/image.png)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/161789/image.png)
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Stephen23
el 19 de Abr. de 2016
Editada: Stephen23
el 19 de Abr. de 2016
In two regexp calls:
>> selected_motor = [1111,4444];
>> C = {'1111 1-2-3';'2222 1-2-3';'3333 4-5-6';'4444 7-8-9';'4444 1-2-3'}
C =
'1111 1-2-3'
'2222 1-2-3'
'3333 4-5-6'
'4444 7-8-9'
'4444 1-2-3'
>> tmp = sprintf('|%d',selected_motor);
>> idx = ~cellfun('isempty',regexp(C,'1-2-3$','once'));
>> idy = ~cellfun('isempty',regexp(C,sprintf('^(%s)',tmp(2:end)),'once'));
>> C(idx & idy)
ans =
'1111 1-2-3'
'4444 1-2-3'
or one regexp call:
>> idz = ~cellfun('isempty',regexp(C,sprintf('^(%s) 1-2-3$',tmp(2:end)),'once'));
>> C(idz)
ans =
'1111 1-2-3'
'4444 1-2-3'
If you wish to experiment with regular expressions, then you can use my FEX submission Regular Expression Helper to create and change regular expressions in real time, and see the outputs in real time:
2 comentarios
Stephen23
el 19 de Abr. de 2016
Editada: Stephen23
el 19 de Abr. de 2016
>> find(idz)
ans =
1 5
But keep in mind that logical indices are the fastest way to index (all of idx, idy and idz are logical indices).
And your questions:
1. This line creates one string containing all of the desired integers that you want to search for, separated by the vertical bar character. The vertical bar has a special meaning in regular expressions: it means "or". So this string tells regexp to match the first integer, or the second, or the third, etc. For my example data this string looks like this:
>> tmp
tmp = |1111|4444
2. This line
idy = ~cellfun('isempty',regexp(C,sprintf('^(%s)',tmp(2:end)),'once'));
creates the regular expression dynamically using sprintf. when you take out the sprintf you can see it is basically the same as your code:
idy = ~cellfun('isempty',regexp(C,...,'once'));
The sprintf creates the correct regular expression to detect the integer:
>> sprintf('^(%s)',tmp(2:end))
ans = ^(1111|4444)
The ^ matches the start of the line, the parentheses are required to group the or parts together. Read the regular expression documentation to learn more.
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