mean value of each row

I have A 500 by 16 matrix and I want to find a mean value of each row and return the result as a 500 by 1.

Does anyone have an idea?

Thank you

[Walter Fanka]

y = yourmatrix;
meanrow_y = mean(y')'

[Walter Roberson]

That should work for 2D arrays like were asked about. However for 3 or more dimensions it would not work and you would need to use a couple of permute() instead. It is a lot easier to just pass in the dimension number like I showed in my Answer.

Answer 1

[Walter Roberson]

mean(YourMatrix,2)

[ava]

Thanks

[William Honjas]

Can you please explain why this is true?

[Jan]

The documentation of mean explains this exhaustively already:

doc mean

The first input is the data, the 2nd the dimension to operate on. Therefore mean(x,2) is the mean over the 2nd dimension, which means the rows.

[Amy Gleckl]

I had a similar issue and this worked perfectly for me, thank you very much!

Answer 2

[sura Naji]

l have amatrix contact from 1 colum and 1000 rows l want to find the mean and the standard deviation also l want to find the worst value of this because l use the particle swarm optimization

[Walter Roberson]

M = mean(amatrix);
S = std(amatrix);
[~, order] = max(abs(amatrix - M));
furthest_from_mean = amatrix(order(1));

Note that the value that is furthest from the mean will also be the value that is the greatest zscore (furthest deviation)

Answer 3

[RAMPUNIT KUMAR]

RAMPUNIT KUMAR less than a minute ago ⋮ I too have a doubt, like for matrix (a b c d e f g h I j k l m n o p q r) I need to find the mean of a,b then c,d then e,f then g,h and so on upto last element. How could we do that if size is big enough.

[Walter Roberson]

syms a b c d e f g h I j k l m n o p q r
matrix = [a b c d e f g h I j k l m n o p q r]

matrix = 

means = (matrix(1:2:end) + matrix(2:2:end))/2

means = 

except that you would use the appropriate numeric values in matrix instead of syms . The syms used here is just for demonstration purposes.