Comparing value in m x n matrices to find its index
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Hi, I have one set of data that I need to compare it with different size of data. So, as it stated in this code below, the threshold will be 3, 3.5, 4, 4.5 ..... I have to compare each threshold with all available data in variable GtrecMRCG2 then get its index. after all data compared, I need to check it with remaining threshold in variable thresholdVAR.
I wrote this based on my understanding. but it doesn't work because the dimension is mismatched. Thank you so much and big appreciation to those who want to give me advises. :)
threshold = 3;
thresholdVAR=[threshold 0 0 0 0 0 0 0 0];
GtrecMRCG2= [ 5 8 9 6 2 5 2 4 6 3 8 9 11];
for ii=1:9
thresholdVAR(ii+1:end)= thresholdVAR(ii)+ 0.5;
end
for idxm=1:length(thresholdVAR)
for idxn = 1:length(GtrecMRCG2)
idxalarmMRCG (1:length(thresholdVAR),1:length(GtrecMRCG2))= find(GtrecMRCG2(idxm,idxn)>=thresholdVAR(idxm,idxn));
end
end
4 comentarios
Jan
el 28 de Abr. de 2016
Please post the complete error message.
Your description is a little bit vague and the code does not run. Therefore I doubt that the given information allows to solve the problem in the way you want.
In the first loop you overwrite the elements multiple times. Perhaps all you want cumsum?
Tifani Utami
el 28 de Abr. de 2016
CS Researcher
el 1 de Mayo de 2016
Not exactly sure what you are trying to achieve but you should see the line with the code:
find( thresholdVAR(idxm:sza(1),idxn:sza(2)) < GtrecMRCG2(1:sza(1),1:sza(2)));
Your thresholdVAR and GtrecMRCG2 are not 2D matrices. They both are 1D vectors.
Also, you don't need a loop to initialize the thresholdVAR. You can just do this:
thresholdVAR = 3:0.5:7;
Tifani Utami
el 2 de Mayo de 2016
Respuesta aceptada
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