Automatic naming of matrix

Hi,

I have a cell matrix of 300,000 x 100 format. By using for loops, I want to make a new matrix every 10,000 rows while naming each different matrix automatically. For instance, a matrix that contains 1:10,000 from the original huge matrix will have something like matrix_1 as follows:

matrix_1 = [1:10,000,:];
matrix_2 = [10,001:20,000,:];
.
.
.
.
matrix_20 = [190,001:200,000,:];

Would you mind sharing your thoughts on this?

Thanks for your help in advance!

Answer 1

[Azzi Abdelmalek]

This is not good, Use instead a cell array

matrix{1} = [1:10];
matrix{2} = [1:20]

http://matlab.wikia.com/wiki/FAQ#How_can_I_create_variables_A1.2C_A2.2C....2CA10_in_a_loop.3F

[Walter Roberson]

blocksize = 10000;
numrow = size(YourMatrix,1);
num_blocks = floor(numrow/blocksize);
blocks = blocksize * ones(1, num_blocks));
rowsused = num_blocks * blocksize;
if rowsused ~= numrow
   blocks(end+1) = numrow - rowused;
end

matrix = mat2cell(YourMatrix, blocks, size(YourMatrix,2));

Now matrix{1} will be the first 10000, matrix{2} will be the second, and so on, and the last entry will have fewer than 10000 if YourMatrix is not an even multiple of 10000 rows.

[Jake]

Thanks Walter! This helps. However, I forgot to mention earlier that the original matrix that I have is based on text.file. So, after running script as you can see below, I have tmp = {284781x1 cell}, which is actually 53 columns (i.e. variables) existing within this cell structure format for each row.

fid = fopen(filename,'r');
tmp = textscan(fid,'%s','Delimiter','\n');

Given a suggested solution you mentioned above, I have 100,000 rows (1X411 char) in each matrix which is remaining a char format.

How can I break each row of char format and convert into cell matrix as a result?? Thus, I want to have a cell matrix of [100,000 x 53] instead of a char matrix of [100,000 x 1]...

Please share your thoughts. Thanks for your help again!!!

[Walter Roberson]

YourMatrix = char(tmp);