code generation for FFT is void

I want to generate code from my m-code which computes an FFT. When I see the results the c-function is void when the result should be a complex double?

Respuestas (1)

Walter Roberson
Walter Roberson el 5 de Mayo de 2016

0 votos

The generated code has pointers passed in to it. C cannot handle multiple outputs, so Mathworks generates code that passes in pointers for all outputs, rather than special-casing the first output.

1 comentario

wietjes
wietjes el 5 de Mayo de 2016
And how do I extract the results from the function?

Iniciar sesión para comentar.

Categorías

Más información sobre MATLAB Coder en Centro de ayuda y File Exchange.

Etiquetas

Preguntada:

el 5 de Mayo de 2016

Comentada:

el 5 de Mayo de 2016

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by