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Reducing time code takes to run using profile viewer

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Paul
Paul el 12 de Feb. de 2012
Cerrada: MATLAB Answer Bot el 20 de Ag. de 2021
This code below takes up about 40 seconds when the size of the matrix is (13,5,2000) All im doing is removing any matrixs which are repeated.
ie if big_data(:,:,x)==big_data(:,:,x+1) then remove one of the matrixs. I know there is a unique function, but I cant seem to get it to work how I want. When I scale it up to matrixs of size (13,5,10000), its just taking too long.
Is there a better way? thanks.
while x<length(big_data(1,1,:))+1
while y<length(big_data(1,1,:))
y=y+1;
if big_data(:,:,x)==big_data(:,:,y)
big_data(:,:,y)=[];
y=y-1;
end
end
x=x+1;
y=x;
end

Respuestas (2)

Jan
Jan el 12 de Feb. de 2012
Shrinking a large array iteratively requires a lot of resouerces, equivalently to growing. Better use a logical vector to mark subarrays and delete them all together after the loops.

Paul
Paul el 14 de Feb. de 2012
Are you saying to do something like, replace
big_data(:,:,y)=[];
with
to_delete(count)=y
then once the loop is finished
big_data(:,:,to_delete)=[]
  1 comentario
Sean de Wolski
Sean de Wolski el 14 de Feb. de 2012
yup.
But be sure to preallocate to_delete.
Or even better use a logical vector:
to_delete = false(1,1,size(big_data,3));
while ...
to_delete(1,1,index) = true
end
etc

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