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fzero Index exceeds matrix dimensions, image processing
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hi everybody, im processing satelite imagenary, the last step in the process is a nonlinear ecuation so I'm using Fzero but it continues telling me that index exceeds matrix dimensions here is my script.
%%%%cargar imagenes%%%%
IM(:,:,2)=double(geotiffread('LC80280452015160LGN00_B2.TIF'));
RED(:,:,4)=double(geotiffread('LC80280452015160LGN00_B4.TIF'));
%%%%%TOA%%%%%%
%Banda Azul=2
A(:,:,2)=IM(:,:,2)*0.00002;
A1(:,:,2)=A(:,:,2)+0.1;
Atoa(:,:,2)=A1(:,:,2)/0.9279549148;
%banda Roja=4
R(:,:,4)=double(RED(:,:,4)*0.00002);
R1(:,:,4)=R(:,:,4)+0.1;
toar(:,:,4)=R1(:,:,4)/0.9279549148;
figure, imshow(toar(:,:,4))
figure, imshow(Atoa(:,:,2))
%%%%Reflectancia superficie%%%%
ASi(:,:,2)=double(geotiffread('B1.TIF'));
RSi(:,:,4)=double(geotiffread('B3.TIF'));
AS(:,:,2)=ASi(:,:,2)/10000;
RS(:,:,4)=RSi(:,:,4)/10000;
%%%%AOT%%%%
F=@(t)((0.665483767.*(Atoa(:,:,2)-0.091226952-((exp(-1 .*(0.242593401+t(:,:,2))).*exp(-1 .*(0.242593401+t(:,:,2))/0.927954915).*AS(:,:,2))./(1-AS(:,:,2).*(0.92.*0.242593401+(1-0.725681).*t(:,:,2)).*exp(-1 .*(0.242593401+t(:,:,2)))))))-t(:,:,2));
X(:,:,2)=fzero(F,1);
%%%Guardar%%%
[im1,Referencia]=geotiffread('LC80280452015160LGN00_B2.TIF');
info=geotiffinfo('LC80280452015160LGN00_B2.TIF');
geotiffwrite('toar',toar,Referencia,'GeoKeyDirectoryTag', info.GeoTIFFTags.GeoKeyDirectoryTag);
this is te equation wich I'm having trouble.
where PTOA, Ps, and Ta are images
1 comentario
dpb
el 11 de Jun. de 2016
>> help fzero
...
fun is the function whose zero is to be
computed. It accepts a scalar x and returns a scalar f
Your function doesn't play by the rules it would appear.
Respuestas (1)
Ian Hunter
el 20 de Feb. de 2019
You probably want to try one of matlab's optimization routines where you've set the optimization function to be at a minimum when your function crosses 0.
fmincon is an example.
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