Borrar filtros
Borrar filtros

How to apply for loop for cell arrays?

1 visualización (últimos 30 días)
Ali Y.
Ali Y. el 16 de Jun. de 2016
Comentada: Ali Y. el 16 de Jun. de 2016
I have a matrix that I want dividing it to n matrices, say n = 2, and do some operations along their lengths. The second chain of ‘for’ loops does what I need when there is one matrix, as in the case of the parent matrix (a). But I can’t apply same procedure for the two cell arrays I have.
clear all
clc
a =(1000-0).*rand(10,2)+0 ;
[r,c] = size(a) ;
mina = [1 7] ;
maxa = [6 10] ;
b = cell(numel(mina),1) ;
for o = 1:numel(mina)
b{o} = a(mina(o): maxa(o),:);
end
max_a= zeros(r,c);
for i = 1:r
for j = 1:c
max_a(i,j) = max(a(1:i,j)) ;
end
end
This following lines was what I tried before but it doesn’t work.
for u = 1:numel(mina)
b2(1:maxa(u),:) = cell2mat(b(u)) ;
for i2 = mina(u):maxa(u)
for j2 = 1:c
max_a {u} = max(b2(1:i2,j2)) ;
end
end
end
  2 comentarios
Guillaume
Guillaume el 16 de Jun. de 2016
With your given example, can you show what the output of your last loop should be, as I've no idea what you're trying to do with it.
Guillaume
Guillaume el 16 de Jun. de 2016
Note that if you have a recent version of matlab, your first max_a is simply:
max_a = cummax(a);

Iniciar sesión para comentar.

Respuesta aceptada

Azzi Abdelmalek
Azzi Abdelmalek el 16 de Jun. de 2016
a =(1000-0).*rand(10,2)+0
[r,c] = size(a)
mina = [1 7] ;
maxa = [6 10] ;
b = cell(numel(mina),1) ;
for o = 1:numel(mina)
b{o} = a(mina(o): maxa(o),:);
end
for k=1:numel(b)
bb=b{k};
[r,c]=size(bb);
max_a= zeros(r,c);
for i = 1:r
for j = 1:c
max_a(i,j) = max(a(1:i,j)) ;
end
end
max_b{k}=max_a
end

Más respuestas (0)

Categorías

Más información sobre Logical en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by