Cannot accèss methods of an Object after modified

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Umit
Umit el 15 de Feb. de 2012
I have following codes as junk.m & junk2.m
classdef junk
properties
myValue = [];
end
methods
function obj = junk() % constructor
obj.myValue = 11;
end
function obj = me()
end
end
end
function junk2()
obj = junk(); % construct an object of myClass
obj.myValue = 2; % set some fancy values to the object
obj2 = myFunction(obj); % pass the object to a nice function
disp(obj2.myValue) % verify that myValue has changed
end
function obj = myFunction(obj3)
obj.myValue = obj3.myValue + 1;
end
When I call this function I get following output for methods
methods(obj2)
Methods for class struct:
amd ctranspose fieldnames ichol linsolve permute struct2cell
cholinc display fields ilu luinc reshape transpose
methods(obj)
Methods for class junk:
junk me
How can I get both junk $ me methods after I call myFunction(Obj) method?

Respuesta aceptada

Honglei Chen
Honglei Chen el 15 de Feb. de 2012
You need to use handle object. Use the following line in your class definition
classdef junk < handle
You can then write your function as
function myFunction(obj)
obj.myValue = obj.myValue+1;
end

Más respuestas (2)

Honglei Chen
Honglei Chen el 15 de Feb. de 2012
You need to instantiate the class first in myFunction. The code as is just create a struct obj in myFunction that has a field named myValue.
function obj = myFunction(obj3)
obj = junk;
obj.myValue = obj3.myValue + 1;
end
BTW, you may want to pay more attention to class names and variable names, make them meaningful.
  2 comentarios
Umit
Umit el 15 de Feb. de 2012
The problem is, this is the basic version of my program, I have a complex series of methods $ functions and I need to update object's properties from another method w/o losing same object's methods. How can I do that with updating objects parameters from different functions (something different than constructor of the object).
Honglei Chen
Honglei Chen el 15 de Feb. de 2012
I started a new answer so I can format the code

Iniciar sesión para comentar.


Umit
Umit el 16 de Feb. de 2012
Great it works fine. Thank you.

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