Aggregating selected variables from multiple mat files
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I have 276 mat files (each corresponds to a month for a specific year starting 1993 till 2015). In these files I have numeric vectors with the same length. Some of these vectors cease to exist after a certain point in time. Other new vectors appear at some point in time. I want to aggregate all these vectors in 1 mat file where all vectors have the same length (which means when a vector ceases to exist it will be filled with nans for the remaining periods and when a vector appears the preceding period will be filled with nans). Any advice about how to do that is greatly appreciated.What facilitates the issue is that one vector 'rssd9999' exists in all 276 mat files. I started a code that led nowhere using the eval function (didn't know how to proceed). I think there are easier methods . Basically what i wanted to say in code format:
clear all
files = dir('bhcf*.mat');
for i = 1:length(files)
load(files(i).name);
a=who('BHC*','rssd9999','RSSD9999','rssd9001','RSSD9001');
for j=1:length(a)
v1 = genvarname(['v' a{j}]);
index= isvarname(a{j});
if index==1 && i==1
% here I want to say v1=v2; for example vBHCK0010=BHCK0010;
%I tried eval([v1 '=a{j};']); but it didn't work
elseif index==0 && i==1
v1=nan(size(rssd9999);
elseif v2==1 && i>1 && the variable existed previously
% here I want to say that v1=[v1;the variable a{j}]
elseif v2==0 && i>1 && the variable existed previously
v1=[v1;nan(size(rssd9999)] ;
elseif v2==1 && i>1 && the variable didn't exist previously
% here I want to say that v1=[nan(size(vrssd999));the variable a{j}]
elseif v2==0 && i>1 && the variable didn't exist previously
v1=[nan(size(vrssd999));nan(size(rssd9999)] ;
end
end
end
5 comentarios
José-Luis
el 29 de Jun. de 2016
I don't understand the issue: change your variable as needed beforehand and place in the array.
Respuestas (1)
Guillaume
el 29 de Jun. de 2016
As I've just said in another question: it is better to load your variable into a structure, simply by giving an output to load, then you can use dynamic field names to access your variables.
The way, I'd do it is load your variables into a 2D cell array (with rows: file, columns: variable name), growing the columns as new variables appear, and at the end fill empty cells with nan arrays of the right size:
Warning, untested code, there may be bugs / typos:
files = dir('bhcf*.mat');
monthlydata = cell(numel(files), 0); %starting empty
varnames = {}; %correspond to columns of monthly data, starting empty
for fileidx = 1 : numel(files) %numel is safer than length
matcontent = load(files(i).name); %get content of file as structure
matvars = fieldnames(matcontent)'; %list of variable in file (transposed into a row vector)
matcontent = struct2cell(matcontent); %convert structure into cell array to make it easier to index
varstokeep = ~cellfun(@isempty, regexpi(matvar, '^BHC.*$|^rsdd(9999|9001)$')); %only keep variables 'BHC*','rssd9999','RSSD9999','rssd9001','RSSD9001'
matcontent = matcontent(varstokeep);
matvars = matvars(varstokeep);
[varexists, varcols] = ismember(matvars, varnames); %identify which variable already have a column in the cell array (and which column)
monthlydata(fileidx, varcols) = matcontent(varexists); copy existing variable into corresponding row and columns
numnewvars = sum(~varexists);
monthlydata = [monthlydata, cell(numel(files), numnewvars)]; %grow by the number of non-existing variables
monthlydata(fileidx, end-numnewvars+1 : end) = matcontent(~varexists); and copy those new variables at the end
varnames = [varnames, matvars(~varexists)]; %append new variable names into list of variables
end
%everything is loaded, now fill up empty cells with nans.
%Assuming that the size can vary by variable iterate over the variables
for varidx = 1 : numel(varnames)
emptyrows = cellfun(@isempty, monthlydata(:, varidx));
nonemptydata = monthlydata(~emptyrows, varidx); %cell array containing the non-empty rows for that variable,
montlydata{emptyrows, varidx} = nan(size(nonemptydata{1})); %fill up with nan of the size of the first non-empty matrix for that column
end
I would certainly not create an endless list of new variables or you'll be back to similar problems when you want to process the lot later on.
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