How do I create a vector array out of certain values of a matrix?
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Hi all,
I have a 76x76 matrix, and I want to make the matrix into a vector array instead. But, the matrix is a symmetric matrix, and I only want the non repeated values. So basically, I only want the values from the top right triangle, excluding the diagonal line of value(which are all 1s). So something like i = (1:75), and j = (i+1:76). I am not too sure how to write this in a function though, so please help.
Thank you very much!
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Respuestas (2)
Guillaume
el 23 de Ag. de 2016
m = reshape(1:76*76, 76, 76); %demo matrix
m(triu(true(size(m)), 1))
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sai kumar s
el 31 de Dic. de 2022
along with the componenets in the upper triangular matrix i need diagonal componenets also. how can i extend the above code.
Voss
el 1 de En. de 2023
U = triu(X,k) returns the element on and above the kth diagonal of X
So, triu(X,0) returns all the elements above the main diagonal, with the main diagonal.
X = magic(6)
triu(X,0)
Robert
el 23 de Ag. de 2016
Using some example data, here is the code using logical indexing to grab all the values of the matrix whose column index is greater than its row index (upper triangle not including the diagonal).
n = 76;
x = magic(n);
[ii,jj] = meshgrid(1:n,1:n);
x(ii>jj)
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Guillaume
el 23 de Ag. de 2016
Note that because you're using meshgrid instead of ndgrid, ii is actually the column indices, and jj the row indices. To make that clearer and avoid future bugs when the matrix is not square, I'd use:
[icols, irows] = meshgrid(1:size(x, 2), 1:size(x, 1));
%or
[irows, icols] = ndgrid(1:size(x, 1), 1:size(x, 2));
Or use triu to build the logical matrix directly.
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