extracting values from text files as matrix format

I have a text file whose format as follows;

******** Week 887 almanac for PRN-01 ********
ID:                         01
Health:                     000
Eccentricity:               0.5846023560E-002

******** Week 887 almanac for PRN-02 ********
ID:                         02
Health:                     000
Eccentricity:               0.1588439941E-001

There are several ***** week ****** exist in the text file. I need to store each values (ID,Health, Eccentricity) as a matrix format. How can I store these values as a matrix or array format?

Answer 1

[Azzi Abdelmalek]

fid=fopen('file.txt')
s=fgetl(fid)
out={}
while ischar(s)
   out{end+1}=regexp(s,'(?<=(ID:|Health:| Eccentricity:))\s+\S+','match','once');
   s=fgetl(fid);
end
fclose(fid)
idx=~cellfun(@isempty,out)
out=strtrim(reshape(out(idx),3,[]))'

Answer 2

[dpb]

I'll presume you'll also want to know the week number...

>> fid=fopen('semet.txt','r');
>> fmt1='%*s Week %f';
   fmt2='ID: %f';
   fmt3='Health: %f';
   fmt4='Eccentricity: %f';
>> d=[];  % empty array for the data
>> while ~feof(fid)  % until reach EOF
     d=[d; ...       % read and concatenate into array 
        cell2mat([textscan(fid,fmt1,'collectoutput',1) ...
                  textscan(fid,fmt2,'collectoutput',1) ...
                  textscan(fid,fmt3,'collectoutput',1) ...
                  textscan(fid,fmt4,'collectoutput',1)]).'];
   end
>> d
d =
887.0000    1.0000         0    0.0058
888.0000    1.0000         0    0.0060
>> fid=fclose(fid);
>>

The in-place augmentation of the array isn't ideal from standpoint of efficiency but unless the file is quite large probably faster than the effort to scan the file and preallocate and it's certainly trivial to code...